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anonymous

  • one year ago

Need help please :)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @ganeshie8 @jakashaka123

  3. anonymous
    • one year ago
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    @deadpool117

  4. anonymous
    • one year ago
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    @iGreen

  5. anonymous
    • one year ago
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    @texaschic101

  6. anonymous
    • one year ago
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    @Music_me

  7. anonymous
    • one year ago
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    @mathmath333

  8. anonymous
    • one year ago
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    @sweetburger

  9. anonymous
    • one year ago
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    idk this one -_-

  10. sweetburger
    • one year ago
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    So which of these do you need help with?

  11. anonymous
    • one year ago
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  12. sweetburger
    • one year ago
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    so all 4 equations u need help with im assuming so lets start with the first

  13. anonymous
    • one year ago
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    yes and ok

  14. sweetburger
    • one year ago
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    Alright so 5x+7 = 5x+6 then you cancell out the 5x on each side and your left with 5=6 which is obviously not true so there are no solutions to this equation.

  15. anonymous
    • one year ago
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    1 ; b

  16. sweetburger
    • one year ago
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    for the next one you have -2x+3x= -3-2x this then simplifies to x=-1 which is one solution

  17. sweetburger
    • one year ago
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    this is one solution because the lines would interesect at only one point

  18. anonymous
    • one year ago
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    okay

  19. sweetburger
    • one year ago
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    For the next question you would multiply everything by 4 to get rid of the denominator and you would have x+3=3x+3 which would reduce to x=0 so one solution once again

  20. sweetburger
    • one year ago
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    Then for the last one x=-14 which is one solution

  21. sweetburger
    • one year ago
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    any other questions?

  22. anonymous
    • one year ago
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    so its 1: b 2 : a 3: a 4: a

  23. sweetburger
    • one year ago
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    ya no c's as that would require a final answer to come out of somethings along the line of 3=3

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spraguer (Moderator)
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