Need help please :)

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Need help please :)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

idk this one -_-
So which of these do you need help with?
so all 4 equations u need help with im assuming so lets start with the first
yes and ok
Alright so 5x+7 = 5x+6 then you cancell out the 5x on each side and your left with 5=6 which is obviously not true so there are no solutions to this equation.
1 ; b
for the next one you have -2x+3x= -3-2x this then simplifies to x=-1 which is one solution
this is one solution because the lines would interesect at only one point
okay
For the next question you would multiply everything by 4 to get rid of the denominator and you would have x+3=3x+3 which would reduce to x=0 so one solution once again
Then for the last one x=-14 which is one solution
any other questions?
so its 1: b 2 : a 3: a 4: a
ya no c's as that would require a final answer to come out of somethings along the line of 3=3

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