paperbacon
  • paperbacon
@ganeshie8 please help. Will fan and medal!!!
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
paperbacon
  • paperbacon
use the unit circle to find the inverse function value in degrees tan -1 sqrt 3
anonymous
  • anonymous
I can help you
paperbacon
  • paperbacon
120 90 60 30

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paperbacon
  • paperbacon
Okay @jameel.saeed
ganeshie8
  • ganeshie8
\[\tan\theta = \dfrac{\sin \theta}{\cos\theta}\] notice that \(\large \dfrac{~~\frac{\sqrt{3}}{2}~~}{\frac{1}{2}} = \sqrt{3}\) |dw:1433338492314:dw|
anonymous
  • anonymous
Only If my fingers weren't broken, I could have been faster than you ganeshia8
paperbacon
  • paperbacon
ganeshie8
  • ganeshie8
done with the first question ?
paperbacon
  • paperbacon
Yes, thank you! :)
ganeshie8
  • ganeshie8
whats the answer
paperbacon
  • paperbacon
60 degrees
ganeshie8
  • ganeshie8
ok good just making sure..
paperbacon
  • paperbacon
Okay :)
ganeshie8
  • ganeshie8
which q are you working on now #3 or #4 ?
paperbacon
  • paperbacon
3
ganeshie8
  • ganeshie8
start by isolating \(\sin\theta\)
ganeshie8
  • ganeshie8
\[3\sin\theta = \sin\theta-1 \] \[2\sin\theta = -1\] \[\sin\theta=-\frac{1}{2}\] look at the unit circle, for what values of theta do you have second coordinate = \(-\frac{1}{2}\) ?

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