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anonymous
 one year ago
@ganeshie8 please help. Will fan and medal!!!
anonymous
 one year ago
@ganeshie8 please help. Will fan and medal!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use the unit circle to find the inverse function value in degrees tan 1 sqrt 3

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0\[\tan\theta = \dfrac{\sin \theta}{\cos\theta}\] notice that \(\large \dfrac{~~\frac{\sqrt{3}}{2}~~}{\frac{1}{2}} = \sqrt{3}\) dw:1433338492314:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Only If my fingers weren't broken, I could have been faster than you ganeshia8

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0done with the first question ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0ok good just making sure..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0which q are you working on now #3 or #4 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0start by isolating \(\sin\theta\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0\[3\sin\theta = \sin\theta1 \] \[2\sin\theta = 1\] \[\sin\theta=\frac{1}{2}\] look at the unit circle, for what values of theta do you have second coordinate = \(\frac{1}{2}\) ?
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