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paperbacon

  • one year ago

@ganeshie8 please help. Will fan and medal!!!

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  1. Paperbacon
    • one year ago
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    use the unit circle to find the inverse function value in degrees tan -1 sqrt 3

  2. anonymous
    • one year ago
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    I can help you

  3. Paperbacon
    • one year ago
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    120 90 60 30

  4. Paperbacon
    • one year ago
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    Okay @jameel.saeed

  5. ganeshie8
    • one year ago
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    \[\tan\theta = \dfrac{\sin \theta}{\cos\theta}\] notice that \(\large \dfrac{~~\frac{\sqrt{3}}{2}~~}{\frac{1}{2}} = \sqrt{3}\) |dw:1433338492314:dw|

  6. anonymous
    • one year ago
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    Only If my fingers weren't broken, I could have been faster than you ganeshia8

  7. Paperbacon
    • one year ago
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  8. ganeshie8
    • one year ago
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    done with the first question ?

  9. Paperbacon
    • one year ago
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    Yes, thank you! :)

  10. ganeshie8
    • one year ago
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    whats the answer

  11. Paperbacon
    • one year ago
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    60 degrees

  12. ganeshie8
    • one year ago
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    ok good just making sure..

  13. Paperbacon
    • one year ago
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    Okay :)

  14. ganeshie8
    • one year ago
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    which q are you working on now #3 or #4 ?

  15. Paperbacon
    • one year ago
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    3

  16. ganeshie8
    • one year ago
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    start by isolating \(\sin\theta\)

  17. ganeshie8
    • one year ago
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    \[3\sin\theta = \sin\theta-1 \] \[2\sin\theta = -1\] \[\sin\theta=-\frac{1}{2}\] look at the unit circle, for what values of theta do you have second coordinate = \(-\frac{1}{2}\) ?

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