1. anonymous

use the unit circle to find the inverse function value in degrees tan -1 sqrt 3

2. anonymous

3. anonymous

120 90 60 30

4. anonymous

Okay @jameel.saeed

5. ganeshie8

$\tan\theta = \dfrac{\sin \theta}{\cos\theta}$ notice that $$\large \dfrac{~~\frac{\sqrt{3}}{2}~~}{\frac{1}{2}} = \sqrt{3}$$ |dw:1433338492314:dw|

6. anonymous

Only If my fingers weren't broken, I could have been faster than you ganeshia8

7. anonymous

8. ganeshie8

done with the first question ?

9. anonymous

Yes, thank you! :)

10. ganeshie8

11. anonymous

60 degrees

12. ganeshie8

ok good just making sure..

13. anonymous

Okay :)

14. ganeshie8

which q are you working on now #3 or #4 ?

15. anonymous

3

16. ganeshie8

start by isolating $$\sin\theta$$

17. ganeshie8

$3\sin\theta = \sin\theta-1$ $2\sin\theta = -1$ $\sin\theta=-\frac{1}{2}$ look at the unit circle, for what values of theta do you have second coordinate = $$-\frac{1}{2}$$ ?