@ganeshie8 please help. Will fan and medal!!!

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use the unit circle to find the inverse function value in degrees tan -1 sqrt 3
I can help you
120 90 60 30

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Okay @jameel.saeed
\[\tan\theta = \dfrac{\sin \theta}{\cos\theta}\] notice that \(\large \dfrac{~~\frac{\sqrt{3}}{2}~~}{\frac{1}{2}} = \sqrt{3}\) |dw:1433338492314:dw|
Only If my fingers weren't broken, I could have been faster than you ganeshia8
done with the first question ?
Yes, thank you! :)
whats the answer
60 degrees
ok good just making sure..
Okay :)
which q are you working on now #3 or #4 ?
3
start by isolating \(\sin\theta\)
\[3\sin\theta = \sin\theta-1 \] \[2\sin\theta = -1\] \[\sin\theta=-\frac{1}{2}\] look at the unit circle, for what values of theta do you have second coordinate = \(-\frac{1}{2}\) ?

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