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anonymous
 one year ago
The accompanying data table lists measured voltage amounts supplied directly to a family’s home. The power supply company states that it has a target power supply of 120 volts. Using these home voltage amounts, test the claim that the mean is 120 volts. Use a 0.05 significance level.
Calculate the test statistic.
anonymous
 one year ago
The accompanying data table lists measured voltage amounts supplied directly to a family’s home. The power supply company states that it has a target power supply of 120 volts. Using these home voltage amounts, test the claim that the mean is 120 volts. Use a 0.05 significance level. Calculate the test statistic.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No one can help if you don't provide all the relevant info.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Day Volts Day Volts 1 124.5 21 124.0 2 123.9 22 123.9 3 123.9 23 123.6 4 123.8 24 124.2 5 123.4 25 123.4 6 123.3 26 123.4 7 123.3 27 123.4 8 123.6 28 123.4 9 123.5 29 123.3 10 124.1 30 124.4 11 123.5 31 123.5 12 123.7 32 123.6 13 124.1 33 123.8 14 123.7 34 123.9 15 123.9 35 123.9 16 124.0 36 123.8 17 124.2 37 123.9 18 123.8 38 123.7 19 123.8 39 123.8 20 123.8 40 123.8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ugh, this isn't an incredibly userfriendly format... Anyway, the first thing to do is compute the mean of the sample, so take the average of the "Volts" data (see the pic below). We'll use a \(Z\) test to compare this sample mean to the predicted mean. \[Z=\frac{123.763120}{0.295858}\approx12.7\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you're at all familiar with the standard normal distribution, the conclusion should be obvious, but if you're not, consult a table of \(z\) scores, like the one linked here: http://www.rochester.edu/college/psc/clarke/201/ztable2.jpg Notice that our calculated \(Z\) is not even listed.
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