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anonymous

  • one year ago

still need help PLEASE

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  1. anonymous
    • one year ago
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    @jameel.saeed @Kainui ANYONE please

  2. Projects
    • one year ago
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    What's your question? I'll try my best to help. c:

  3. anonymous
    • one year ago
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  4. anonymous
    • one year ago
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    multiply

  5. Projects
    • one year ago
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    Is it a multiple choice question? If so, would you list the choices?

  6. anonymous
    • one year ago
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    (3a+12)(a+4)^2-(3a+12)/(a^2-25)(a+3.5)^2-0.25(a^2-25)

  7. anonymous
    • one year ago
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    |dw:1433343201369:dw|

  8. anonymous
    • one year ago
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    @jameel.saeed you lost me with all those numbers .-. @Projects those are the choices

  9. Projects
    • one year ago
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    Okay well let's work this out step-by-step. (3a+12(a+4)^4 equals?

  10. Projects
    • one year ago
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    (3a+12)(a+4)^4 **

  11. anonymous
    • one year ago
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    3*(a+4)^5

  12. Projects
    • one year ago
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    You remember PEMDAS?|dw:1433343689511:dw|

  13. anonymous
    • one year ago
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    yes i can recall that

  14. Projects
    • one year ago
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    Okay, good well let's through and do this now. (4a+16)^2 - (3a+12) 4a + 3a equals 7a so now, (7a+16)^2 - (3a+12) 16 + 12 equals 28 (7a+28)^2 (35a)^2 (1225a)

  15. anonymous
    • one year ago
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    so it would be the second one right?

  16. anonymous
    • one year ago
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    Good work @projects

  17. Projects
    • one year ago
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    Now for the other half you got (1225a) / (a^2-25)(a+3.5)^2-0.25(a^2-25) (1225a) / (a^2-25)(a+3.5)^2 Whenever you see a "blank" variable with any raised power, there's a 1 in front of it so, (1225a) / (1a^2-25)(a+3.5)^2-0.25(a^2-25) (1225a) / (2a-25)(a+3.5)^2-0.25(a^2-25) (1225a) / (2a-25)(a+3.5)^2 (1225a) / (2a-21.5)^2 (1225a) / (-19.5a)^2 (1225a) / (380.25a) Thanks @jameel.saeed lol trying my best, lol

  18. Projects
    • one year ago
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    (1225a) / (380.25a)-0.25(a^2-25) You think you could do this one @Armadillo ??

  19. Projects
    • one year ago
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    Sorry, I'm all disoriented right now. :s

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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