A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Write each expression in the standard form for a complex number, a + bi.
[(1 / 2)(cos(72°)) + isin(72°)]5
[√1(cos(3π /14)) + isin(3π /14)]7
[√5(cos(5π / 16)) + isin(5π / 16)]4
[3√7(cos(π / 18)) + isin(π / 18)]6
anonymous
 one year ago
Write each expression in the standard form for a complex number, a + bi. [(1 / 2)(cos(72°)) + isin(72°)]5 [√1(cos(3π /14)) + isin(3π /14)]7 [√5(cos(5π / 16)) + isin(5π / 16)]4 [3√7(cos(π / 18)) + isin(π / 18)]6

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 Can you help me? You don't have to explain every problem, just help me understand the basics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0take the number out front and raise it to the power then multiply the angle by the power

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Seems simple enough, is that all?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(\frac{1}{2}\left(\cos(72^\circ)+i\sin(72^\circ)\right)^5\] \[=\frac{1}{2^5}\left(\cos(72\times 5)+i\sin(72\times 5)\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes it is real easy of course you still have to do the arithmetic, then evaluate the functions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{32}\left(\cos(360)+i\sin(360)\right)\] \[\frac{1}{32}\left(1+0\right)\]\[\frac{1}{32}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Seems simple enough, is that all?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.