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anonymous

  • one year ago

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle. 3 to the 2 over 3 power inches squared 3 to the 8 over 3 power inches squared 9 inches squared 9 to the 2 over 3 power inches squared

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  1. anonymous
    • one year ago
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    Let's find the length, what's the cube root of 81?

  2. anonymous
    • one year ago
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    um dont I multiply 81 by 3? to find it

  3. anonymous
    • one year ago
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    No Cuberoot(3x3x3x3) Cuberoot(3^3 x 3)=?????

  4. anonymous
    • one year ago
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    So I multiply 81 with 3x3x3x3

  5. anonymous
    • one year ago
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    No 3x3x3x3 =81 I just factored the number so you can se tha it's formed by 3x3x3x3 Now the cube root will eliminate 3 of these 3 of the the root, So you get 3cbrt(3)

  6. anonymous
    • one year ago
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    Now, the width A number raised to a fraction can be transformed into a root like this A^b/c Croot(a^b) So 2 to the2/3 Will be cube root of 2^2 How much is Cube root of 2^2?

  7. anonymous
    • one year ago
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    4?

  8. anonymous
    • one year ago
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    So we get cube root of four. Now the area of a rectangle is Width times length How much is Cuberoot of 4 x 3x cuberoot of 3????

  9. anonymous
    • one year ago
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    36?

  10. anonymous
    • one year ago
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    @gaos

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