anonymous
  • anonymous
A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle. 3 to the 2 over 3 power inches squared 3 to the 8 over 3 power inches squared 9 inches squared 9 to the 2 over 3 power inches squared
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Let's find the length, what's the cube root of 81?
anonymous
  • anonymous
um dont I multiply 81 by 3? to find it
anonymous
  • anonymous
No Cuberoot(3x3x3x3) Cuberoot(3^3 x 3)=?????

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anonymous
  • anonymous
So I multiply 81 with 3x3x3x3
anonymous
  • anonymous
No 3x3x3x3 =81 I just factored the number so you can se tha it's formed by 3x3x3x3 Now the cube root will eliminate 3 of these 3 of the the root, So you get 3cbrt(3)
anonymous
  • anonymous
Now, the width A number raised to a fraction can be transformed into a root like this A^b/c Croot(a^b) So 2 to the2/3 Will be cube root of 2^2 How much is Cube root of 2^2?
anonymous
  • anonymous
4?
anonymous
  • anonymous
So we get cube root of four. Now the area of a rectangle is Width times length How much is Cuberoot of 4 x 3x cuberoot of 3????
anonymous
  • anonymous
36?
anonymous
  • anonymous
@gaos

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