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anonymous
 one year ago
Algebra 2 help please!!! I really am in need of help, will FAN and Medal!!!
anonymous
 one year ago
Algebra 2 help please!!! I really am in need of help, will FAN and Medal!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Create an equation. Use the graph below to create the equation of the rainbow parabola.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know I should use the equation y=a(xh)^2+k, but what would I put into the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm.... im not sure have you ever dona a question like this before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've done a question like this before, it's just a confusing topic.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0All I know so far is that I have to create an equation using the graph and I can start by using y=a(xh)^2+k and substituing the vertex (0, 36) for h and k.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I figured most of it out :In order to create an equation using the graph, I can start by using y=a(xh)^2+k and substituting the vertex (0, 36) for h and k and a point (6, 0) for x and y. This will create the equation 0=a(60)^2+36. Now, I just have to solve for a: 0=a(60)^2+36 >>> 0=a(6)^2+36 >>> 0=a(36)+36 >>> 0=a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well actually for this I wouldn't have to solve for a, so the equation would just be 0=a(60)^2+36 right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1vertex is ((0,36)\) and it opens down so it must be \[y=ax^2+36\] for some negative number \(a\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1since it is zero at \(6\) and \(6\) you can pretty much guess that it is \[y=x^2+36\]because that has the two zeros you want

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, I'm a bit confused. How did you get y=ax^2+36?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1or you could multiply out \[a(x6)(a+6)=a(x^236)\] then replace \(x\) by \(0\), set the result equal 36 and solve \[a(036)=36\] for \(a\) and see that \(a=1\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you see from the picture that the vertex is \((0,36)\) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For this problem, I don't have to solve for a, I just need to create an equation and then use it for the next 2 questions about the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because after I create an equation, I have to answer this: Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i just looked at your solution above, and it is right you got \[y=x^2+36\]which is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok, thank you!! can you help me with the second question pertaining to the graph which is: Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.
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