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Someone please help

I know I should use the equation y=a(x-h)^2+k, but what would I put into the equation?

hello

Hi

hmmm.... im not sure have you ever dona a question like this before

i hate algebra

I've done a question like this before, it's just a confusing topic.

HI!!

Hello! :)

vertex is ((0,36)\) and it opens down so it must be
\[y=ax^2+36\] for some negative number \(a\)

Wait, I'm a bit confused. How did you get y=ax^2+36?

ok lets go slow

you see from the picture that the vertex is \((0,36)\) right?

i just looked at your solution above, and it is right
you got
\[y=-x^2+36\]which is correct