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HI!!

for a line, derivative = slope

Number 2!

ok so first replacing \(x\) by \(2\) we have
\[\frac{f(2+h)-f(2)}{h}\]

in this case \[f(x)=5x+9\] so
\[f(2)=5\times 2+9=19\]

When plugging it in isn't it supposed to look like this?:\[\frac{ (5(x+h)+9)-(5x+9) }{ h }\]

it is if you use x instead of 2

since it makes no difference lets do it your way

Oh, okay. I didn't realize you could plug in 2 right away - I just always did it at the end

you can almost do it in your head
\[5x+5h+9-5x-9=5h\]

lol your welcome
\[\color\magenta\heartsuit\]