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JozelynW

  • one year ago

How do you make a exponential graph that represents f(x)=100(1+0.7)^x ?

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  1. JozelynW
    • one year ago
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    @mathmate

  2. JozelynW
    • one year ago
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    @peachpi

  3. JozelynW
    • one year ago
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    @mathmate @Thesmarterone

  4. mathmate
    • one year ago
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    Hint: |dw:1433363568951:dw| Here you have a=100, b=1.07 just need a few more points to give the shape of the graph.

  5. JozelynW
    • one year ago
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    you don't need the points of x and y> @mathmate

  6. mathmate
    • one year ago
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    The graph that I drew free-hand is sufficient for most purposes. Some teachers require at least one more point so that the graph defines completely the function.

  7. mathmate
    • one year ago
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    The graph that I drew free-hand is sufficient for most purposes. Some teachers require at least one more point so that the graph defines completely the function.

  8. JozelynW
    • one year ago
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    @mathmate what point? like f(1)=170 ,a point like this.

  9. mathmate
    • one year ago
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    Looked at it again, the graph is actually \(y=100(1.7^x)\), my bad! Except for b=1.7 (and not 1.07), the graph holds. Typically in a graph of an exponential function \(f(x)=a(b^x)\) f(0)=a, (because x=0, f(0)=\(ab^0=a, because b^0=1\) This point was indicated on the graph. f(1)=ab (because x=1, f(1)=\(ab^1=ab\)

  10. mathmate
    • one year ago
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    Yes, one more point like f(1)=170 defines the function completely, since a and b will then be defined.

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