anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
sqrt[6]{125a^15}
anonymous
  • anonymous
with what
anonymous
  • anonymous
\[\sqrt[6]{125a^1}\]

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More answers

anonymous
  • anonymous
a^15 my bad
anonymous
  • anonymous
\[\sqrt{5} ^15
Nnesha
  • Nnesha
convert 6th root to exponent \[\huge\rm \sqrt[n]{x^m} = x^\frac{ m }{ n }\]
anonymous
  • anonymous
\[\sqrt[5]{15}\]
anonymous
  • anonymous
like this
Nnesha
  • Nnesha
nope it's 6th root so n = 6 |dw:1433351042568:dw| so \[\huge\rm \sqrt[6]{a^{15}} = a^\frac{ ? }{ ? } \]
anonymous
  • anonymous
a^15/6
Nnesha
  • Nnesha
yep right now reduce the fraction
anonymous
  • anonymous
5/2
anonymous
  • anonymous
so a 5/2 is the answer
anonymous
  • anonymous
nope
Nnesha
  • Nnesha
not done a^5/2 \[\huge\rm a^\frac{ a \times a \times a \times a \times a }{ a \times a }\] can u cancel out 2 a's or in other words how many times 2 goes into 5 ?
anonymous
  • anonymous
2
anonymous
  • anonymous
times
Nnesha
  • Nnesha
yep right so 5/2 2 times so 4-5 = 1 that's mean a stay under the root and one a^2 u can write it outside the root |dw:1433351567387:dw| now factor 125
Nnesha
  • Nnesha
5^what power =125 ?
Nnesha
  • Nnesha
a^5/2 can be written as \[\huge\rm \sqrt{a^5} = \sqrt{a^2 \times a^2 \times a}\] (when we multiply same bases we should add their exponent ) square cancels with square root so \[a \times a \sqrt{a} = a^2 \sqrt{a}\]

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