BATMAN31
  • BATMAN31
I am doing this experiment, and have reached the point where you apply snell's law, and I don't get it. Link is in the comments.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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BATMAN31
  • BATMAN31
http://www.education.com/science-fair/article/refraction-fast-light-travel-air/
anonymous
  • anonymous
LINK
BATMAN31
  • BATMAN31
number 9.

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BATMAN31
  • BATMAN31
how does this equation work? walk me through it
anonymous
  • anonymous
you need the numbers that go in the equation ...
BATMAN31
  • BATMAN31
27 and 17
anonymous
  • anonymous
which is sin and which is V
BATMAN31
  • BATMAN31
neither, from this experiment I do not know any values for 4.
BATMAN31
  • BATMAN31
the WIP equation is \[(\sin 17)/(\sin 27)=v1/v2\]
anonymous
  • anonymous
@Nnesha @iGreen
BATMAN31
  • BATMAN31
I just watched the khan academy vid on snell's law, and it didn't clear much up. @directrix
anonymous
  • anonymous
@amistre64
anonymous
  • anonymous
yeah i dont understand
BATMAN31
  • BATMAN31
@Michele_Laino
Michele_Laino
  • Michele_Laino
here is a little explanation: |dw:1433353958208:dw| the statement of the Snell's law is: \[\Large {n_1}\sin {\theta _1} = {n_2}\sin {\theta _2}\]
Michele_Laino
  • Michele_Laino
since the light speed v in amedium with refractive index n, is: \[\Large v = \frac{c}{n}\] then we can divide both sides of the Snell's law by c, so we get: \[\Large \frac{{{n_1}}}{c}\sin {\theta _1} = \frac{{{n_2}}}{c}\sin {\theta _2}\]
Michele_Laino
  • Michele_Laino
now, according to the previous formula, we have: \[\Large {v_1} = \frac{c}{{{n_1}}},\quad {v_2} = \frac{c}{{{n_2}}}\]
Michele_Laino
  • Michele_Laino
then the statement of the Snell's law can be rewritten as follows: \[\Large \frac{{\sin {\theta _1}}}{{{v_1}}} = \frac{{\sin {\theta _2}}}{{{v_2}}}\] and finally: \[\Large \frac{{\sin {\theta _1}}}{{\sin {\theta _2}}} = \frac{{{v_1}}}{{{v_2}}}\]
BATMAN31
  • BATMAN31
@Michele_Laino are you still here? I still don't get it. I was eating
BATMAN31
  • BATMAN31
@paki @texaschic101
Michele_Laino
  • Michele_Laino
why?
Michele_Laino
  • Michele_Laino
please, read my step-by-step explanation

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