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anonymous

  • one year ago

Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6. a. 0 b. 1 c. 2

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  1. anonymous
    • one year ago
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    @amoodarya

  2. anonymous
    • one year ago
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    can you help

  3. amoodarya
    • one year ago
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    one way to solve is : using law of cosine find "c" then you can find number of triangle \[b^2+c^2-a^2=2(b)(c) \cos(A)\\36-16+c^2=2(6)(c)\cos(30)\]

  4. amoodarya
    • one year ago
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    or using law of sine \[\frac{ \sin(A) }{ a }=\frac{ \sin(B) }{ b}\\\frac{\sin30}{4}=\frac{\sin(B)}{6}\\sin(B)=\frac{3}{4}\]

  5. anonymous
    • one year ago
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    how can i get my answer from 3/4?

  6. amoodarya
    • one year ago
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    B=?

  7. anonymous
    • one year ago
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    6

  8. amoodarya
    • one year ago
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    can you find B?

  9. amoodarya
    • one year ago
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    angle of B ?

  10. anonymous
    • one year ago
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    i dont know how

  11. amoodarya
    • one year ago
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    |dw:1433356975331:dw|

  12. amoodarya
    • one year ago
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    B=48.5 or B=180-48.5

  13. anonymous
    • one year ago
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    131.5?

  14. anonymous
    • one year ago
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    thats not one of my answers?

  15. anonymous
    • one year ago
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    is the answer 1?

  16. anonymous
    • one year ago
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    i think its 2

  17. amoodarya
    • one year ago
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    then c=? a=30 b=131.5 , b=48.5

  18. amoodarya
    • one year ago
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    number of possibilities is ?

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