Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6. a. 0 b. 1 c. 2

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Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6. a. 0 b. 1 c. 2

Mathematics
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can you help
one way to solve is : using law of cosine find "c" then you can find number of triangle \[b^2+c^2-a^2=2(b)(c) \cos(A)\\36-16+c^2=2(6)(c)\cos(30)\]

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or using law of sine \[\frac{ \sin(A) }{ a }=\frac{ \sin(B) }{ b}\\\frac{\sin30}{4}=\frac{\sin(B)}{6}\\sin(B)=\frac{3}{4}\]
how can i get my answer from 3/4?
B=?
6
can you find B?
angle of B ?
i dont know how
|dw:1433356975331:dw|
B=48.5 or B=180-48.5
131.5?
thats not one of my answers?
is the answer 1?
i think its 2
then c=? a=30 b=131.5 , b=48.5
number of possibilities is ?

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