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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    This is a multiple choice question, so I can provide the choices if needed.

  2. anonymous
    • one year ago
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    you know how graph of cosx looks like?

  3. anonymous
    • one year ago
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    wavey

  4. anonymous
    • one year ago
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    right. and at x=0 it is equal 1

  5. anonymous
    • one year ago
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    here are my choices, maybe they will help.

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  6. anonymous
    • one year ago
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    im with you so far

  7. anonymous
    • one year ago
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    from the graph of cosx you can see that it repeatedly goes from -1 through 0 to 1. sec x = 1/cosx so i think you can notice that when cosx=0 secx will have a problem. Right?

  8. anonymous
    • one year ago
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    Right!

  9. anonymous
    • one year ago
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    all the options are wavey and do this though

  10. anonymous
    • one year ago
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    what will sec(x) be equal to when cos(x)=0 ?

  11. anonymous
    • one year ago
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    0 as well? it can't be -0

  12. anonymous
    • one year ago
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    it can aproach 0 from negative side of y-axis or from positive side. There is no such a thing like -0

  13. anonymous
    • one year ago
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    what will sec(x) be equal to when cos(x)=0 ?

  14. anonymous
    • one year ago
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    alright so A and B as well as C and D both have the same shaped wave, so is it the outer lines in the corners we need to look at?

  15. anonymous
    • one year ago
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    cosx=1 at x=0. So A,B are not correct since there it equals 0 and not 1

  16. anonymous
    • one year ago
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    Well having it narrowed down helps, how do we determine which of C and D is the correct answer now?

  17. anonymous
    • one year ago
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    ask yourself this question: what will sec(x) be equal to when cos(x)=0 ?

  18. anonymous
    • one year ago
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    1?

  19. anonymous
    • one year ago
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    I think i'm just going with C

  20. anonymous
    • one year ago
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    thanks for the help

  21. anonymous
    • one year ago
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    what is 1/0=?

  22. anonymous
    • one year ago
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    you cannot divide by 0, can you?

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spraguer (Moderator)
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