chillhill
  • chillhill
Solve the inequality x^2<16
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

chillhill
  • chillhill
Solve the inequality x^2<16
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
The above answer is false. If you were to solve this problem as if it were an equal sign, you would normally square root both sides and get an answer of x = +/- 4. In this case, though, we will do the same thing, but consider something slightly different. If \(x^{2} < 16\), then we have: \(\sqrt{x^{2}} < \sqrt{16}\) \(|x| < 4\) Here we introduce the concept that \(\sqrt{x^2}\) = |x|. Without knowing this, square rooting both sides gives us something silly. So, that being said, we now have the ineqaulity |x| < 4. When you have an absolutely value inequality in the form |x| < a, this is equivalent to saying -a < x < a. GIven that, |x| < 4 is equaivalent to -4 < x < 4. What I did may seem a little odd, so ask me if something doesnt make sense and I can try and reexplain or we can take a different approach to solving this :)
anonymous
  • anonymous
Just to clarify, after all that the answer is -4 < x < 4. I didnt want that to get lost in what I said, lol.
chillhill
  • chillhill
Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Great job @Concentrationalizing! I misread the equation as x^2 = 16 not x^2 < 16. Thank you for correcting me! :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.