anonymous
  • anonymous
Hey can someone please help me out with this? I'll fan and medal :) Write x^2 - 2x - 3 = 0 in the form (x - a)^2 = b, where a and b are integers. (x - 4)^2 = 3 (x - 3)^2 = 2 (x - 2)^2 = 1 (x - 1)^2 = 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Vocaloid @iGreen @wio @Kainui
anonymous
  • anonymous
complete the square
anonymous
  • anonymous
do you know how to do that?

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anonymous
  • anonymous
Umm, kind of. Could you help walk me through it?
anonymous
  • anonymous
sure
anonymous
  • anonymous
Ok, so I'm not sure where to start...
anonymous
  • anonymous
sorry about that
anonymous
  • anonymous
first step is to move the -3 to the other side of the equation
anonymous
  • anonymous
No problem :)
anonymous
  • anonymous
so add 3 to both sides to get x^2 - 2x = 3
anonymous
  • anonymous
Ok, so it would read x^2 - 2x = 3?
anonymous
  • anonymous
Oh, wait that's what you put lol
anonymous
  • anonymous
that's right
anonymous
  • anonymous
Ok, and then I might try to factor?
anonymous
  • anonymous
|dw:1433358733396:dw|
anonymous
  • anonymous
now divide the -2x by -2
anonymous
  • anonymous
this gives you 1
anonymous
  • anonymous
|dw:1433358802037:dw|
anonymous
  • anonymous
then you square 1 and put it back into the equation
anonymous
  • anonymous
which gives
anonymous
  • anonymous
|dw:1433358865720:dw|
anonymous
  • anonymous
Wait, I think I got lost somewhere. So after you divide the -2x by -2, you have to divide the other side of the equation by -2 which gives you the equation x^2 - x = -1.5. Right?
anonymous
  • anonymous
no, not when completing the square. we are only looking at the right side of the equation right now
anonymous
  • anonymous
sorry, i meant the left side of the equation
anonymous
  • anonymous
Hmmm, I'm still lost.
anonymous
  • anonymous
all we are doing is adding a number to the left side of the equation so we get a factor for x with multiplicity 2
anonymous
  • anonymous
we then add that same number to the right side of the equation
anonymous
  • anonymous
i think you will understand it when I go through all the steps
anonymous
  • anonymous
so we added 1 to x^2 - 2x on the left side of the equation. since we added 1 to one side of the equation, we now add 1 to the other side
anonymous
  • anonymous
Ok, so now the equation is x^2 + 1 = 4
anonymous
  • anonymous
|dw:1433359235489:dw|
anonymous
  • anonymous
the -2x is still there
anonymous
  • anonymous
Wait I meant x^2 -2x + 1 = 4
anonymous
  • anonymous
Yeah :)
anonymous
  • anonymous
thats right, now factor x^2-2x+1
anonymous
  • anonymous
I think this is where I get lost
anonymous
  • anonymous
I know how to factor but this one is different lol I guess
anonymous
  • anonymous
ok, what two numbers multiply together to get 1
anonymous
  • anonymous
1 and 1
anonymous
  • anonymous
add them together
anonymous
  • anonymous
2 :)
anonymous
  • anonymous
its suppose to add to -2 so 1 and 1 doesn't work.
anonymous
  • anonymous
Oh, ok so it would have to be -1 and -1
anonymous
  • anonymous
what other 2 numbers multiply together to get 1
anonymous
  • anonymous
that's right
anonymous
  • anonymous
so what does the equation look like factored?
anonymous
  • anonymous
Oh, I think I got it (maybe)! Is it (x - 1)^2 = 4?
anonymous
  • anonymous
good job! :)
anonymous
  • anonymous
Yay! Thank you so much @10115658 It makes perfect sense now. :) I am now officially a fan ;)
anonymous
  • anonymous
awesome
anonymous
  • anonymous
Tttyl and thanks again :)
anonymous
  • anonymous
*ttyl

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