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q2 – 20/500 = 0.04 q – √ 0.04 = 0.2 p – 1 – 0.2 = 0.8 p2 –0.82 = 0.64 2pq –2x(0.8)x(0.2) = 0.08 Scenario #2 Conclusion Questions Use this information to help you answer the following questions. The original population’s actual genotype frequencies were: HH – 0.58; Hh – 0.26; hh – 0.16 Is the current population in Hardy-Weinberg equilibrium? Yes or No Is the current population evolving? Yes or No If the current population is evolving, what type of effect is responsible for genetic drift?

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