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anonymous
 one year ago
Tension in the rope at the rigid end is (g=10m/s^2)


60kg O (Upward Acceleration 2m/s^2)

50kg O (Downward 2m/s)

40kg O (Downward accelration 1m/s^2)
OPTIONS:
A) 760N
B)1360N
C)1580N
D)1620N
anonymous
 one year ago
Tension in the rope at the rigid end is (g=10m/s^2)   60kg O (Upward Acceleration 2m/s^2)  50kg O (Downward 2m/s)  40kg O (Downward accelration 1m/s^2) OPTIONS: A) 760N B)1360N C)1580N D)1620N

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1if you want help, maybe scan and post the original question or draw something helpful :p acceleration and rope?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0K here is the original question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0FYI the answer is 1580N I just dunnoe how! :((((((((((

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1ok, try it as a simple static mass question. but adjust gravity for each climber so for the first one, accelerating upwards at 2m/s, use g = 9.8 +2 for the others, use g = 9.82 and g= 9.8  1. where does that take you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cuz its 11.8 X 60 + 7.8X 50 + 40X 8.8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the question lets us approximate g=10m/s^2 :\

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If i take g=10 and do what u said then I get 1480N

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2here is my reasoning: on the rope is acting the three weight forces of the corresponding people, so the reaction opposed by the rigid end is: (60+40+50)*10=1500 Newtons. Furthermore, the person of 50 Kg is going upward, so the rigid end is applying a force directly downward, which is 60*2=+120 Newtons, the person of 50 Kg is moving by uniform motion, so he is not applying any force on a rope, apart his weight, which is already computed. Finally the person of 40 Kg is going downward, so the rigid end is applying a force directed upward, which is 1*40=40 Newton. Then the force applied by the rigid end, of the rope is: 1500+12040=1580 Newtons

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1** the person of 50 Kg is moving by uniform motion** missed that tots. B is measured in \(\frac{m}{s}\), not \(\frac{m}{s^2}\) that means (10 + 2) X 60 + (10 + 0) X 50 + (10  1) X 40 = 1580N

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1thanks @Michele_Laino

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1aplos @sahana2397 i need to learn to read

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2thanks! @IrishBoy123

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2you are good in physics! @IrishBoy123

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1@Michele_Laino and you are better :))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino and @IrishBoy123 thanks a ton!!!! :)))))) literally broke my head all day abt this!!! I can finally go to sleep!!! You both rock! P.S @IrishBoy123 i need to learn to read properly aswell :P
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