anonymous
  • anonymous
Tension in the rope at the rigid end is (g=10m/s^2) -----|----- | 60kg O (Upward Acceleration 2m/s^2) | 50kg O (Downward 2m/s) | 40kg O (Downward accelration 1m/s^2) OPTIONS: A) 760N B)1360N C)1580N D)1620N
Physics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
I MEANT rope
IrishBoy123
  • IrishBoy123
if you want help, maybe scan and post the original question or draw something helpful :p acceleration and rope?
anonymous
  • anonymous
k one sec

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
K here is the original question
anonymous
  • anonymous
FYI the answer is 1580N I just dunnoe how! :((((((((((
IrishBoy123
  • IrishBoy123
ok, try it as a simple static mass question. but adjust gravity for each climber so for the first one, accelerating upwards at 2m/s, use g = 9.8 +2 for the others, use g = 9.8-2 and g= 9.8 - 1. where does that take you?
anonymous
  • anonymous
1450N?
anonymous
  • anonymous
cuz its 11.8 X 60 + 7.8X 50 + 40X 8.8
anonymous
  • anonymous
but the question lets us approximate g=10m/s^2 :\
anonymous
  • anonymous
If i take g=10 and do what u said then I get 1480N
anonymous
  • anonymous
Michele_Laino
  • Michele_Laino
here is my reasoning: on the rope is acting the three weight forces of the corresponding people, so the reaction opposed by the rigid end is: (60+40+50)*10=1500 Newtons. Furthermore, the person of 50 Kg is going upward, so the rigid end is applying a force directly downward, which is 60*2=+120 Newtons, the person of 50 Kg is moving by uniform motion, so he is not applying any force on a rope, apart his weight, which is already computed. Finally the person of 40 Kg is going downward, so the rigid end is applying a force directed upward, which is -1*40=-40 Newton. Then the force applied by the rigid end, of the rope is: 1500+120-40=1580 Newtons
IrishBoy123
  • IrishBoy123
** the person of 50 Kg is moving by uniform motion** missed that tots. B is measured in \(\frac{m}{s}\), not \(\frac{m}{s^2}\) that means (10 + 2) X 60 + (10 + 0) X 50 + (10 - 1) X 40 = 1580N
IrishBoy123
  • IrishBoy123
IrishBoy123
  • IrishBoy123
aplos @sahana2397 i need to learn to read
Michele_Laino
  • Michele_Laino
thanks! @IrishBoy123
Michele_Laino
  • Michele_Laino
you are good in physics! @IrishBoy123
IrishBoy123
  • IrishBoy123
@Michele_Laino and you are better :-))
IrishBoy123
  • IrishBoy123
much better
anonymous
  • anonymous
@Michele_Laino and @IrishBoy123 thanks a ton!!!! :)))))) literally broke my head all day abt this!!! I can finally go to sleep!!! You both rock! P.S @IrishBoy123 i need to learn to read properly aswell :P

Looking for something else?

Not the answer you are looking for? Search for more explanations.