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anonymous

  • one year ago

HEEEEEEEEEEEEELPPPP! HELP! HELP!!!!! EMERGENCY!!!!!!!!!!!!!!!!! @Thesmartone @hero @kainui @wio

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  1. anonymous
    • one year ago
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    and your questions is? .-.

  2. anonymous
    • one year ago
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    @Luigi0210 @Nnesha @ParthKohli

  3. anonymous
    • one year ago
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    @ganeshie8 think she wants you .-.

  4. anonymous
    • one year ago
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    The probability of finding a broken cookie in a bag of chocolate chip cookies is P= .03. Find the probability of getting at least 2 broken cookies in a bag containing 36 cookies. A) .91 B) .294 C) .33 D) .06 @ganeshie8

  5. ganeshie8
    • one year ago
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    binomial distribution

  6. ganeshie8
    • one year ago
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    P(X>=2) = 1 - P(X=0) + P(X=1)

  7. ganeshie8
    • one year ago
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    do you know how to find P(X=0), the probabiltiy for getting 0 broken cookies ?

  8. anonymous
    • one year ago
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    no :/ i dont get this at all

  9. ganeshie8
    • one year ago
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    thats ok notice that probability for getting a broken cookie = 0.03 therefore probability for NOT getting a broken cookie = 0.97 yes ?

  10. ganeshie8
    • one year ago
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    since we want 0 broken cookies : P(X=0) = 0.97^36

  11. anonymous
    • one year ago
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    so its 0.33??

  12. ganeshie8
    • one year ago
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    thats the probability for getting 0 broken cookies but thats not the answer

  13. anonymous
    • one year ago
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    oh okay

  14. ganeshie8
    • one year ago
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    next find the probabilty for getting 1 broken cookie

  15. anonymous
    • one year ago
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    ok what is next? how did u find .294?

  16. ganeshie8
    • one year ago
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    did you get how we arrived at 0.33 for the probability of getting 0 broken cookies ?

  17. anonymous
    • one year ago
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    yes sir!

  18. ganeshie8
    • one year ago
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    good, similarly see if you can find the probability of getting 1 broken cookie

  19. ganeshie8
    • one year ago
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    give it a try

  20. anonymous
    • one year ago
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    I'm not sure.. i tried but i don't know how to get it

  21. anonymous
    • one year ago
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    @ganeshie8

  22. ganeshie8
    • one year ago
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    1 broken cookie means, 35 unbroken cookies, yes ?

  23. anonymous
    • one year ago
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    yes

  24. ganeshie8
    • one year ago
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    so the probability is 0.03*0.97^35 ?

  25. ganeshie8
    • one year ago
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    but wait, that broken cookie could be either 1st or 2nd or 3rd or... 36th there are 36 ways it can happen so the probability for getting 1 broken cookie is actually 36* 0.03*0.97^35

  26. anonymous
    • one year ago
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    okay so that will be 0.2?

  27. ganeshie8
    • one year ago
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    try again, im getting 0.37 something

  28. anonymous
    • one year ago
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    i just want to know how u got .294

  29. anonymous
    • one year ago
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    yeah same.. i just rounded it

  30. anonymous
    • one year ago
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    0.4 i meant sorry

  31. ganeshie8
    • one year ago
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    so the probability of getting at least 2 broken cookies is \[\large 1-(.97^{36} + 36*0.03*0.97^{35})\]

  32. anonymous
    • one year ago
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    okay thank you so much!! appreciate it!

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