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anonymous
 one year ago
HEEEEEEEEEEEEELPPPP! HELP! HELP!!!!! EMERGENCY!!!!!!!!!!!!!!!!! @Thesmartone @hero @kainui @wio
anonymous
 one year ago
HEEEEEEEEEEEEELPPPP! HELP! HELP!!!!! EMERGENCY!!!!!!!!!!!!!!!!! @Thesmartone @hero @kainui @wio

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and your questions is? ..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 @Nnesha @ParthKohli

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 think she wants you ..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The probability of finding a broken cookie in a bag of chocolate chip cookies is P= .03. Find the probability of getting at least 2 broken cookies in a bag containing 36 cookies. A) .91 B) .294 C) .33 D) .06 @ganeshie8

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3binomial distribution

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3P(X>=2) = 1  P(X=0) + P(X=1)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3do you know how to find P(X=0), the probabiltiy for getting 0 broken cookies ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no :/ i dont get this at all

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3thats ok notice that probability for getting a broken cookie = 0.03 therefore probability for NOT getting a broken cookie = 0.97 yes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3since we want 0 broken cookies : P(X=0) = 0.97^36

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3thats the probability for getting 0 broken cookies but thats not the answer

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3next find the probabilty for getting 1 broken cookie

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok what is next? how did u find .294?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3did you get how we arrived at 0.33 for the probability of getting 0 broken cookies ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3good, similarly see if you can find the probability of getting 1 broken cookie

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure.. i tried but i don't know how to get it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.31 broken cookie means, 35 unbroken cookies, yes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3so the probability is 0.03*0.97^35 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3but wait, that broken cookie could be either 1st or 2nd or 3rd or... 36th there are 36 ways it can happen so the probability for getting 1 broken cookie is actually 36* 0.03*0.97^35

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so that will be 0.2?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3try again, im getting 0.37 something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just want to know how u got .294

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah same.. i just rounded it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3so the probability of getting at least 2 broken cookies is \[\large 1(.97^{36} + 36*0.03*0.97^{35})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you so much!! appreciate it!
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