anonymous
  • anonymous
please help ^.^
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@geekfromthefutur
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geekfromthefutur
  • geekfromthefutur
That's devil math xD
anonymous
  • anonymous
thanks anyway XD

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Nnesha
  • Nnesha
can u use unit circle ?
anonymous
  • anonymous
all that I know have to do is draw the angle given, and then find cosine and sine, I don't think it matters how I get it done I just have to show my work
Nnesha
  • Nnesha
i like degrees so if you want you can convert radians to degree 7pi/4 times 180/pi
anonymous
  • anonymous
ok so 315 degrees?
Nnesha
  • Nnesha
yes right which is |dw:1433361087764:dw|in 4th quadrant
anonymous
  • anonymous
alright
Nnesha
  • Nnesha
|dw:1433361160024:dw| draw a right traingle near to the axis we need that reference angle which is 45 360-315 = 45 now you have to use 45-45-90 triangle
anonymous
  • anonymous
ok I think I understand...
Nnesha
  • Nnesha
http://prntscr.com/7crrp5 right here |dw:1433361396623:dw| sin = opposite over hypotenuse cos = adjacent over hypotenuse
Nnesha
  • Nnesha
|dw:1433361539015:dw| what is opposite side of 45 angle ?
Nnesha
  • Nnesha
do you now how to find 45-45-90 triangle from the unit circle ?
anonymous
  • anonymous
I'm a little lost.. I know that 1 is opposite the 45
Nnesha
  • Nnesha
yes right and hypotenuse is the longest side of right triangle which is ?
anonymous
  • anonymous
the squroot 2
anonymous
  • anonymous
square root*
anonymous
  • anonymous
oh whatever you know what I mean
Nnesha
  • Nnesha
yes right so \[\huge\rm sin =\frac{ 1 }{ \sqrt{2} }\] no radicals should be at the denominator so that's why we have to multiply both top and bottom by sqrt{2} \[\huge\rm sin =\frac{ 1 }{ \sqrt{2} } \times \frac{\sqrt{2}}{\sqrt{2}}\] sovle that
Nnesha
  • Nnesha
solve*
anonymous
  • anonymous
umm... \[\frac{ \sqrt{2} }{ 2 }\] ?
Nnesha
  • Nnesha
yes right
Nnesha
  • Nnesha
-.- guess? well that's right now cos = adjacent over hyp so cos= ?
anonymous
  • anonymous
oh yay!
anonymous
  • anonymous
so \[\frac{ 45 }{ \sqrt{2} }\]
anonymous
  • anonymous
(and it wasn't a guess, i was just trying to remember when I had learned that, hoping I did it right from my memory)
Nnesha
  • Nnesha
nope adjacent (side that touchz|dw:1433362268317:dw| the angle )
Nnesha
  • Nnesha
adjacent = 1
anonymous
  • anonymous
oh so \[\frac{1 }{ \sqrt{2} }\]
anonymous
  • anonymous
...right?
Nnesha
  • Nnesha
yes right solve that
anonymous
  • anonymous
wouldn't it be the same as the other one?
Nnesha
  • Nnesha
yes right so (x ,y) x represent cosine y coordinate represent sin for signs remember CAST rule |dw:1433362536321:dw|
anonymous
  • anonymous
whoa just got a little lost...
Nnesha
  • Nnesha
alright it's okay so what part u didn't understand ?? :-)
anonymous
  • anonymous
why do we need (x, y) what part of the problem does that fit into?
Nnesha
  • Nnesha
yes that's what you need cosine and sin value |dw:1433362805558:dw|
Nnesha
  • Nnesha
x coordinate represent cosine y represent sin and that order pair we just found which is cosine = sqrt{2}/2 sin =sqrt{2}/2
anonymous
  • anonymous
|dw:1433362859876:dw| so you're saying this is x, and this is y?
Nnesha
  • Nnesha
nope all angles ha' one x and one y value |dw:1433362920755:dw| unit circle is almost like normal x y graph CAST rule is easy to remember negative and plus signs like we are in 4th quadrant where only cos values are positive sin is negative and tan is negative so angle 315 cosine and sin value are \[(\frac{ \sqrt{2} }{ 2 } , -\frac{ \sqrt{2} }{ 2 })\]
Nnesha
  • Nnesha
http://prntscr.com/7cs6pe here is a unit cricle
Nnesha
  • Nnesha
circle*
anonymous
  • anonymous
\[\left( \frac{ \sqrt{2} }{ 2 }, \frac{ \sqrt{2} }{ 2 } \right)\] so then wouldn't it be like this?
anonymous
  • anonymous
I don't get why the second is negative....
Nnesha
  • Nnesha
yes right but it's in 4th quadrant where y values are negative right so sin suppose to be negative
anonymous
  • anonymous
OH because sine is negative... sorry
Nnesha
  • Nnesha
|dw:1433363153305:dw|
Nnesha
  • Nnesha
it's like normal x y graph |dw:1433363292356:dw|
anonymous
  • anonymous
OMG IT JUST CLICKED!!! that took my brain way too long >.<
Nnesha
  • Nnesha
:-)
anonymous
  • anonymous
@geekfromthefutur perhaps you'd like a math lesson? XD

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