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anonymous

  • one year ago

please help ^.^

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  1. anonymous
    • one year ago
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    @geekfromthefutur

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  2. geekfromthefutur
    • one year ago
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    That's devil math xD

  3. anonymous
    • one year ago
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    thanks anyway XD

  4. Nnesha
    • one year ago
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    can u use unit circle ?

  5. anonymous
    • one year ago
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    all that I know have to do is draw the angle given, and then find cosine and sine, I don't think it matters how I get it done I just have to show my work

  6. Nnesha
    • one year ago
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    i like degrees so if you want you can convert radians to degree 7pi/4 times 180/pi

  7. anonymous
    • one year ago
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    ok so 315 degrees?

  8. Nnesha
    • one year ago
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    yes right which is |dw:1433361087764:dw|in 4th quadrant

  9. anonymous
    • one year ago
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    alright

  10. Nnesha
    • one year ago
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    |dw:1433361160024:dw| draw a right traingle near to the axis we need that reference angle which is 45 360-315 = 45 now you have to use 45-45-90 triangle

  11. anonymous
    • one year ago
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    ok I think I understand...

  12. Nnesha
    • one year ago
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    http://prntscr.com/7crrp5 right here |dw:1433361396623:dw| sin = opposite over hypotenuse cos = adjacent over hypotenuse

  13. Nnesha
    • one year ago
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    |dw:1433361539015:dw| what is opposite side of 45 angle ?

  14. Nnesha
    • one year ago
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    do you now how to find 45-45-90 triangle from the unit circle ?

  15. anonymous
    • one year ago
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    I'm a little lost.. I know that 1 is opposite the 45

  16. Nnesha
    • one year ago
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    yes right and hypotenuse is the longest side of right triangle which is ?

  17. anonymous
    • one year ago
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    the squroot 2

  18. anonymous
    • one year ago
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    square root*

  19. anonymous
    • one year ago
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    oh whatever you know what I mean

  20. Nnesha
    • one year ago
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    yes right so \[\huge\rm sin =\frac{ 1 }{ \sqrt{2} }\] no radicals should be at the denominator so that's why we have to multiply both top and bottom by sqrt{2} \[\huge\rm sin =\frac{ 1 }{ \sqrt{2} } \times \frac{\sqrt{2}}{\sqrt{2}}\] sovle that

  21. Nnesha
    • one year ago
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    solve*

  22. anonymous
    • one year ago
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    umm... \[\frac{ \sqrt{2} }{ 2 }\] ?

  23. Nnesha
    • one year ago
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    yes right

  24. Nnesha
    • one year ago
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    -.- guess? well that's right now cos = adjacent over hyp so cos= ?

  25. anonymous
    • one year ago
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    oh yay!

  26. anonymous
    • one year ago
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    so \[\frac{ 45 }{ \sqrt{2} }\]

  27. anonymous
    • one year ago
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    (and it wasn't a guess, i was just trying to remember when I had learned that, hoping I did it right from my memory)

  28. Nnesha
    • one year ago
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    nope adjacent (side that touchz|dw:1433362268317:dw| the angle )

  29. Nnesha
    • one year ago
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    adjacent = 1

  30. anonymous
    • one year ago
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    oh so \[\frac{1 }{ \sqrt{2} }\]

  31. anonymous
    • one year ago
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    ...right?

  32. Nnesha
    • one year ago
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    yes right solve that

  33. anonymous
    • one year ago
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    wouldn't it be the same as the other one?

  34. Nnesha
    • one year ago
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    yes right so (x ,y) x represent cosine y coordinate represent sin for signs remember CAST rule |dw:1433362536321:dw|

  35. anonymous
    • one year ago
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    whoa just got a little lost...

  36. Nnesha
    • one year ago
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    alright it's okay so what part u didn't understand ?? :-)

  37. anonymous
    • one year ago
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    why do we need (x, y) what part of the problem does that fit into?

  38. Nnesha
    • one year ago
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    yes that's what you need cosine and sin value |dw:1433362805558:dw|

  39. Nnesha
    • one year ago
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    x coordinate represent cosine y represent sin and that order pair we just found which is cosine = sqrt{2}/2 sin =sqrt{2}/2

  40. anonymous
    • one year ago
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    |dw:1433362859876:dw| so you're saying this is x, and this is y?

  41. Nnesha
    • one year ago
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    nope all angles ha' one x and one y value |dw:1433362920755:dw| unit circle is almost like normal x y graph CAST rule is easy to remember negative and plus signs like we are in 4th quadrant where only cos values are positive sin is negative and tan is negative so angle 315 cosine and sin value are \[(\frac{ \sqrt{2} }{ 2 } , -\frac{ \sqrt{2} }{ 2 })\]

  42. Nnesha
    • one year ago
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    http://prntscr.com/7cs6pe here is a unit cricle

  43. Nnesha
    • one year ago
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    circle*

  44. anonymous
    • one year ago
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    \[\left( \frac{ \sqrt{2} }{ 2 }, \frac{ \sqrt{2} }{ 2 } \right)\] so then wouldn't it be like this?

  45. anonymous
    • one year ago
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    I don't get why the second is negative....

  46. Nnesha
    • one year ago
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    yes right but it's in 4th quadrant where y values are negative right so sin suppose to be negative

  47. anonymous
    • one year ago
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    OH because sine is negative... sorry

  48. Nnesha
    • one year ago
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    |dw:1433363153305:dw|

  49. Nnesha
    • one year ago
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    it's like normal x y graph |dw:1433363292356:dw|

  50. anonymous
    • one year ago
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    OMG IT JUST CLICKED!!! that took my brain way too long >.<

  51. Nnesha
    • one year ago
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    :-)

  52. anonymous
    • one year ago
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    @geekfromthefutur perhaps you'd like a math lesson? XD

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