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anonymous

  • one year ago

having a VERY difficult time trying to solve combination/permutation problems? it's not clicking!?!??! At the Peking Gardens restaurant, the menu features 5 items in column A, 6 in column B, 4 in column D, 8 in column E, and 5 in column F. For a NOBEL plate, you can order one item from each of columns A, B, C. How many different NOBEL plates are there? For an IMPERIAL plate, you can order two items from each of columns A, B and C or two each from columns D, E, and F. How many IMPERIAL plates can be ordered? How would I solve this?

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  1. campbell_st
    • one year ago
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    this is fundamental theorem of counting but you are missing the number in column C A = 5 B = 6 C = ? D = 4 E = 5 F = 8 Nobel plate = 5 x 6 x ? just multiply the number of choices in each stage...

  2. campbell_st
    • one year ago
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    for the 2nd part the imperial it uses combinations column A selecting 2 from 5 which is \[^5 C _{2} ~~or ~~\left(\begin{matrix}5 \\ 2\end{matrix}\right)\]

  3. anonymous
    • one year ago
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    oh i understood the noble part, but im a bit confused for the imperial plate

  4. anonymous
    • one year ago
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    if it's or, do i need to add the ABC and DEF columns together after multiplying?

  5. anonymous
    • one year ago
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    how would i do it with only factorial? @campbell_st

  6. campbell_st
    • one year ago
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    again its multiplying 2 from A \[^5C_{2}\] 2 from B \[^6C_{2}\] continue this the the solution is \[^5C_{2} \times ~^6C_{2} \times .... \]

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