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anonymous

  • one year ago

Hey I just need someone to check my answer on this. I'll fan and medal :) The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2 - 0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year. I think the average rate of change is 2.38?

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  1. anonymous
    • one year ago
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    How did you get 2.38?

  2. anonymous
    • one year ago
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    Well, I plugged in 2 for every t in the equation, and then I plugged in 6 for every t in the equation. I solved them, took the difference and divided it by the number of years between 2 and 6, so, 4.

  3. anonymous
    • one year ago
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    So the first equation was f(2) = 3.5 and the second equation was f(6) = 9.5.

  4. anonymous
    • one year ago
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    Yes, those are correct.

  5. anonymous
    • one year ago
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    So the average rate of change IS 2.38??

  6. anonymous
    • one year ago
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    9.5 - 3.5 would give you the average rate of change.

  7. anonymous
    • one year ago
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    Yes, but they are asking the average rate of change, in thousands, PER YEAR. I think that is just overall change. :)

  8. anonymous
    • one year ago
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    But 9.5 - 3.5 = 6 and then you divide 6 by the number of years which would be 4 so 6/4 = 1.5. I think that 2.38 is wrong...

  9. anonymous
    • one year ago
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    It's asking in thousand of people, the answer does not have to be in the thousands place.

  10. anonymous
    • one year ago
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    Ok I'm not sure what you mean but my question is asking the average rate of change per year, not overall. :D

  11. anonymous
    • one year ago
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    Average rate of change from t :2 to t:6, so the change in those intervals, that would be the difference between 9.5 and 3.5.

  12. anonymous
    • one year ago
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    Maybe you could read the question again just to make sure? I still think they are asking for it per year... :)

  13. anonymous
    • one year ago
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    I think that I'll just go with 1.5. Thanks though. Ttyl :)

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