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- anonymous

Hey I just need someone to check my answer on this. I'll fan and medal :)
The function below shows the number of car owners f(t), in thousands, in a city in different years t:
f(t) = 0.25t^2 - 0.5t + 3.5
The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.
I think the average rate of change is 2.38?

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- anonymous

- schrodinger

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- anonymous

How did you get 2.38?

- anonymous

Well, I plugged in 2 for every t in the equation, and then I plugged in 6 for every t in the equation. I solved them, took the difference and divided it by the number of years between 2 and 6, so, 4.

- anonymous

So the first equation was f(2) = 3.5 and the second equation was f(6) = 9.5.

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- anonymous

Yes, those are correct.

- anonymous

So the average rate of change IS 2.38??

- anonymous

9.5 - 3.5 would give you the average rate of change.

- anonymous

Yes, but they are asking the average rate of change, in thousands, PER YEAR. I think that is just overall change. :)

- anonymous

But 9.5 - 3.5 = 6 and then you divide 6 by the number of years which would be 4 so 6/4 = 1.5. I think that 2.38 is wrong...

- anonymous

It's asking in thousand of people, the answer does not have to be in the thousands place.

- anonymous

Ok I'm not sure what you mean but my question is asking the average rate of change per year, not overall. :D

- anonymous

Average rate of change from t :2 to t:6, so the change in those intervals, that would be the difference between 9.5 and 3.5.

- anonymous

Maybe you could read the question again just to make sure? I still think they are asking for it per year... :)

- anonymous

I think that I'll just go with 1.5. Thanks though. Ttyl :)

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