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anonymous
 one year ago
Hey I just need someone to check my answer on this. I'll fan and medal :)
The function below shows the number of car owners f(t), in thousands, in a city in different years t:
f(t) = 0.25t^2  0.5t + 3.5
The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.
I think the average rate of change is 2.38?
anonymous
 one year ago
Hey I just need someone to check my answer on this. I'll fan and medal :) The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t^2  0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year. I think the average rate of change is 2.38?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get 2.38?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I plugged in 2 for every t in the equation, and then I plugged in 6 for every t in the equation. I solved them, took the difference and divided it by the number of years between 2 and 6, so, 4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the first equation was f(2) = 3.5 and the second equation was f(6) = 9.5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, those are correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the average rate of change IS 2.38??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09.5  3.5 would give you the average rate of change.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but they are asking the average rate of change, in thousands, PER YEAR. I think that is just overall change. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But 9.5  3.5 = 6 and then you divide 6 by the number of years which would be 4 so 6/4 = 1.5. I think that 2.38 is wrong...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's asking in thousand of people, the answer does not have to be in the thousands place.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I'm not sure what you mean but my question is asking the average rate of change per year, not overall. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Average rate of change from t :2 to t:6, so the change in those intervals, that would be the difference between 9.5 and 3.5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe you could read the question again just to make sure? I still think they are asking for it per year... :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think that I'll just go with 1.5. Thanks though. Ttyl :)
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