anonymous
  • anonymous
AB and BC are tangents of the circle with the center at D. The measure of ACD = 15°. Which is the measure of ABC?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Anyone
campbell_st
  • campbell_st
can you post a diagram
anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/4fa870bae4b059b524f46cba-bdboy0-1336438977297-3878fd319c389fd12f9e5f82b179f44f.gif

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campbell_st
  • campbell_st
ok this is what you should know tangents from a external point are equal.. so AB = BC and tangents and radii intersect at right angles... so angle BAD = BCD ( both 90) triangle CDA is isosceles ( since CD and CD are equal radii) so if ACD = 15 then Angle CAD = 15 ( bass angles of an isosceles triangle) now you can find angle ADC from angle sum of a triangle and then you can find angle ABC by angle sum of a quadrilateral ABC = 360 - 90 - 90 - ADC hope it helps
anonymous
  • anonymous
Wait so it's 165?

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