At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
If X-Y=3..how can you change this equation to show what Y equals?
idk this..... @Black_ninja123
I'm not good at this
IF X -Y =3....then if we add Y to both sides we get X= 3 +Y.....now subtract 3 from both sides and what do you get?
If you subtract 3 from both sides of x=3+y ????
I really have a hard time understanding this...
Now you know from the second equation that y = x-3....substitute x-3 for y in the first equation and solve for x.
if y=x-3, then you could substitute. 4x+y=2 4x+(x-3)=2 ^ see what i did there? 5x-3=2 +3 +3 ------- 5x=5 /5 /5 ----- x=1
@DJBreezy you following me so far?
I never was good at this but i wont leave a User hanging :) here https://www.symbolab.com/solver/system-of-equations-calculator/4x%2By%3D2%2CX-Y%3D3/?origin=button
then once you solved for x, you can plug that into one of the simpler equations and solve for y. Once you solve for both y and x, then you will have the points
I wish it wouldnt should show the answer but the steps....
is the answer 1,-3??
well let's see x-y=3 **plug in the value of x...x=1** 1-y=3 -1 -1 ------ -y=2 y=-2
Maybe you might wanna follow @Jamierox4ev3r a little more,and maybe,just maybe you might get an idea of how to do it on your own. :)
Great work @Jamierox4ev3r
Does the substitution make sense @DJBreezy ? Just find the value of one variable, then substitute it into an equation
BRUHHH.....If ur not helping y are u in my question.....everyone fails at something @Here_to_Help15