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AmTran_Bus

  • one year ago

Log differentiation?

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  1. AmTran_Bus
    • one year ago
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    My answer http://www.wolframalpha.com/input/?i=differentiate+y%3Dx%5E%282%2Fx%29

  2. AmTran_Bus
    • one year ago
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    But which one matches the one from wolfram?

  3. AmTran_Bus
    • one year ago
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    I really think it is a.

  4. xapproachesinfinity
    • one year ago
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    you are trying to differentiate \[y=x^{\frac{2}{x}}\]

  5. AmTran_Bus
    • one year ago
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    yep

  6. xapproachesinfinity
    • one year ago
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    what did you do so far?

  7. AmTran_Bus
    • one year ago
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    typed in wolfram.

  8. xapproachesinfinity
    • one year ago
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    hehe i mean on your own

  9. xapproachesinfinity
    • one year ago
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    if you know already the answer from wolfram why are you still needing help

  10. AmTran_Bus
    • one year ago
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    The answer from wolfram dont match one of the choices I posted. Can you check for me

  11. xapproachesinfinity
    • one year ago
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    hmm interesting! so wolfram given you an retriceanswer

  12. AmTran_Bus
    • one year ago
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    Its just in a different form.

  13. xapproachesinfinity
    • one year ago
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    well you could start with \[\Large y=e^{2\frac{\ln x}{x}}\]

  14. xapproachesinfinity
    • one year ago
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    that base change performed there

  15. xapproachesinfinity
    • one year ago
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    now you can differentiate it can you not?

  16. xapproachesinfinity
    • one year ago
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    \[D(e^u)=\frac{du}{dx}e^u\]

  17. xapproachesinfinity
    • one year ago
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    chain rule

  18. xapproachesinfinity
    • one year ago
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    so it would be \[\Large y'=D(2\frac{\ln x}{x})e^{2\frac{\ln x}{x}}\]

  19. xapproachesinfinity
    • one year ago
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    D mean derivative

  20. xapproachesinfinity
    • one year ago
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    seems to me it will get to one of your answer choices

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spraguer (Moderator)
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