AmTran_Bus
  • AmTran_Bus
Log differentiation?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
AmTran_Bus
  • AmTran_Bus
My answer http://www.wolframalpha.com/input/?i=differentiate+y%3Dx%5E%282%2Fx%29
AmTran_Bus
  • AmTran_Bus
But which one matches the one from wolfram?
AmTran_Bus
  • AmTran_Bus
I really think it is a.

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More answers

xapproachesinfinity
  • xapproachesinfinity
you are trying to differentiate \[y=x^{\frac{2}{x}}\]
AmTran_Bus
  • AmTran_Bus
yep
xapproachesinfinity
  • xapproachesinfinity
what did you do so far?
AmTran_Bus
  • AmTran_Bus
typed in wolfram.
xapproachesinfinity
  • xapproachesinfinity
hehe i mean on your own
xapproachesinfinity
  • xapproachesinfinity
if you know already the answer from wolfram why are you still needing help
AmTran_Bus
  • AmTran_Bus
The answer from wolfram dont match one of the choices I posted. Can you check for me
xapproachesinfinity
  • xapproachesinfinity
hmm interesting! so wolfram given you an retriceanswer
AmTran_Bus
  • AmTran_Bus
Its just in a different form.
xapproachesinfinity
  • xapproachesinfinity
well you could start with \[\Large y=e^{2\frac{\ln x}{x}}\]
xapproachesinfinity
  • xapproachesinfinity
that base change performed there
xapproachesinfinity
  • xapproachesinfinity
now you can differentiate it can you not?
xapproachesinfinity
  • xapproachesinfinity
\[D(e^u)=\frac{du}{dx}e^u\]
xapproachesinfinity
  • xapproachesinfinity
chain rule
xapproachesinfinity
  • xapproachesinfinity
so it would be \[\Large y'=D(2\frac{\ln x}{x})e^{2\frac{\ln x}{x}}\]
xapproachesinfinity
  • xapproachesinfinity
D mean derivative
xapproachesinfinity
  • xapproachesinfinity
seems to me it will get to one of your answer choices

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