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anonymous

  • one year ago

area of a parallelogram did i do this right ?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    i got 105?

  3. geerky42
    • one year ago
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    Yeah 105 is correct answer.

  4. geerky42
    • one year ago
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    what about unit?

  5. anonymous
    • one year ago
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    thanks and um that would be cm

  6. geerky42
    • one year ago
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    No. \(\text{cm}\times\text{cm} = \text{cm}^2\), right?

  7. geerky42
    • one year ago
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    Since you did \(7~\text{cm}\times 15~\text{cm}\)

  8. anonymous
    • one year ago
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    oh yes i forgot sorry

  9. geerky42
    • one year ago
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    okay, so answer is \(105~\text{cm}^2\)

  10. anonymous
    • one year ago
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    ok so @geerky42 is this right

  11. geerky42
    • one year ago
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    Unit is wrong

  12. geerky42
    • one year ago
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    You did \(\dfrac{1}{2} (8~\text{cm}\times10~\text{cm}) \)

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    so cm3

  15. geerky42
    • one year ago
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    How?

  16. anonymous
    • one year ago
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    1/2 x 8 x 10

  17. geerky42
    • one year ago
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    1/2 has no unit

  18. anonymous
    • one year ago
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    oh wait cm2

  19. geerky42
    • one year ago
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    yeah

  20. anonymous
    • one year ago
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    ok

  21. geerky42
    • one year ago
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    You can treat units like variable

  22. geerky42
    • one year ago
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    \(\text{cm}\times\text{cm} = \text{cm}^2\) Just like how \(x\times x = x^2\)

  23. anonymous
    • one year ago
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    ah ok that makes more sense

  24. anonymous
    • one year ago
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    i see

  25. anonymous
    • one year ago
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    what about this

  26. anonymous
    • one year ago
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    @geerky42

  27. geerky42
    • one year ago
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    Area should be \(3.14~\text{yd}^2\)

  28. anonymous
    • one year ago
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    how is that

  29. geerky42
    • one year ago
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    Because you have \(\pi r^2\) So you squared unit too.

  30. geerky42
    • one year ago
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    \[\pi r^2~~~\rightarrow~~~\pi(1~\text{yd})^2\]

  31. anonymous
    • one year ago
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    ohh

  32. geerky42
    • one year ago
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    Yeah. What about circumference?

  33. anonymous
    • one year ago
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    ok and my circumference is 6.28yd2

  34. geerky42
    • one year ago
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    why \(\text{yd}^2\)?

  35. anonymous
    • one year ago
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    2*3.14

  36. geerky42
    • one year ago
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    \[2\pi r ~~~\rightarrow~~~2\pi(1~\text{yd})\]

  37. geerky42
    • one year ago
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    that "2" has no unit.

  38. anonymous
    • one year ago
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    ah ok so circumference is usually 1pi

  39. geerky42
    • one year ago
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    \[C = 2\pi (1~\text{yd})\]

  40. geerky42
    • one year ago
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    So 6.28 yd

  41. anonymous
    • one year ago
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    yeah that's the formula i used

  42. anonymous
    • one year ago
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    ok

  43. anonymous
    • one year ago
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    im not sure what to do here

  44. geerky42
    • one year ago
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    It's basically semicircle subtract triangle

  45. anonymous
    • one year ago
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    if the radius is 6 that means the diameter is 12

  46. anonymous
    • one year ago
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    huh? so how do I start to solve

  47. geerky42
    • one year ago
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    find area of triangle and area of semicircle, then you do semicircle - triangle

  48. anonymous
    • one year ago
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    ah ok onr sec

  49. anonymous
    • one year ago
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    wait but only the height is given for the triangle how would i find the base

  50. geerky42
    • one year ago
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    |dw:1433376534008:dw|

  51. geerky42
    • one year ago
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    So base (aka diameter) is 12 yd.

  52. anonymous
    • one year ago
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    ok i got that because diameter is twice as much as radius

  53. geerky42
    • one year ago
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    yeah. Do you understand how I got base.

  54. anonymous
    • one year ago
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    no how is the diameter the base

  55. anonymous
    • one year ago
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    ?

  56. geerky42
    • one year ago
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    Try imagine rotating height into base, then you will see that height is half the base.

  57. geerky42
    • one year ago
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    |dw:1433377025268:dw|

  58. geerky42
    • one year ago
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    Height is also radius.

  59. anonymous
    • one year ago
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    ok

  60. geerky42
    • one year ago
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    Still don't understand?

  61. anonymous
    • one year ago
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    i see

  62. anonymous
    • one year ago
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    so what is my next step

  63. geerky42
    • one year ago
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    Find areas

  64. geerky42
    • one year ago
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    "find area of triangle and area of semicircle, then you do semicircle - triangle"

  65. anonymous
    • one year ago
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    ok so then i have 36 for the triangle and 56.52

  66. anonymous
    • one year ago
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    and you get 20.52

  67. geerky42
    • one year ago
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    yeah

  68. geerky42
    • one year ago
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    That's your answer.

  69. geerky42
    • one year ago
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    unit is?

  70. anonymous
    • one year ago
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    thanks that wasn't hard

  71. geerky42
    • one year ago
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    yeah.

  72. anonymous
    • one year ago
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    yd1

  73. geerky42
    • one year ago
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    \(\text{yd}^2\)?

  74. anonymous
    • one year ago
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    srry typo

  75. geerky42
    • one year ago
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    oh okay

  76. geerky42
    • one year ago
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    yeah 2

  77. anonymous
    • one year ago
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    hey do you know about midpoint

  78. geerky42
    • one year ago
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    yeah

  79. anonymous
    • one year ago
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  80. anonymous
    • one year ago
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    i would do x1+x2/2 y1+y2/2 right

  81. geerky42
    • one year ago
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    Yeah

  82. geerky42
    • one year ago
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    \[\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)\]

  83. anonymous
    • one year ago
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    ok i think i got this wring

  84. anonymous
    • one year ago
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    (4,-12/2) @geerky42

  85. geerky42
    • one year ago
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    \((-4, -6)\)

  86. geerky42
    • one year ago
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    \[\left(\dfrac{-6+-2}{2},\dfrac{-8+-4}{2}\right)\]

  87. geerky42
    • one year ago
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    \[\left(\dfrac{-8}{2},\dfrac{-12}{2}\right)\]

  88. anonymous
    • one year ago
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    8 divided by 2 is 4

  89. geerky42
    • one year ago
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    yeah, so -8 divide by 2 is -4.

  90. anonymous
    • one year ago
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    oh

  91. anonymous
    • one year ago
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    what about this @geerky42

  92. anonymous
    • one year ago
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    @geerky42

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