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Bananas1234
 one year ago
Simplify completely: square root of 81y^5
Bananas1234
 one year ago
Simplify completely: square root of 81y^5

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Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0i dont think that is what i need sorry.

Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0options: A. 9y^2 square root y B. 3y^2 C. 3y^2 square root 2y D. 9y square root y

Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0ok i think that makes sense

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0Whats the square root of 81?

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0good \[\huge~9*(y*y*y*y*y)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{81y^{5}} = \sqrt{81}*\sqrt{y^{4}}*\sqrt{y}\] You can think of it like this, which seems to be the approach of pooja above. Good luck :)

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0I agree with that. @Concentrationalizing is it right though? :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, given \[\sqrt{81y^{5}} = \sqrt{81} * \sqrt{y^{4}} * \sqrt{y}\] \(\sqrt{81} = 9\) For the \(\sqrt{y^{4}}\) part, if we think of the square root as being an exponent of 1/2, we have: \[\sqrt{y^{4}} = y^{4*\frac{1}{2}} = y^{2}\] The \(\sqrt{y}\) part cannot be simplified. Put it all together and we have \(9y^{2}\sqrt{y}\)

Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0i think i understand that, Thank you!
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