Bananas1234
  • Bananas1234
Simplify completely: square root of 81y^5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
59049
Bananas1234
  • Bananas1234
i dont think that is what i need sorry.
Bananas1234
  • Bananas1234
options: A. 9y^2 square root y B. 3y^2 C. 3y^2 square root 2y D. 9y square root y

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Bananas1234
  • Bananas1234
ok
Bananas1234
  • Bananas1234
why?
Bananas1234
  • Bananas1234
ok i think that makes sense
Bananas1234
  • Bananas1234
ok thanks!
pooja195
  • pooja195
Whats the square root of 81?
Bananas1234
  • Bananas1234
9
pooja195
  • pooja195
good \[\huge~9*(y*y*y*y*y)\]
anonymous
  • anonymous
\[\sqrt{81y^{5}} = \sqrt{81}*\sqrt{y^{4}}*\sqrt{y}\] You can think of it like this, which seems to be the approach of pooja above. Good luck :)
Bananas1234
  • Bananas1234
9y
Bananas1234
  • Bananas1234
9y square root y?
Bananas1234
  • Bananas1234
@pooja195
pooja195
  • pooja195
I agree with that. @Concentrationalizing is it right though? :/
anonymous
  • anonymous
Well, given \[\sqrt{81y^{5}} = \sqrt{81} * \sqrt{y^{4}} * \sqrt{y}\] \(\sqrt{81} = 9\) For the \(\sqrt{y^{4}}\) part, if we think of the square root as being an exponent of 1/2, we have: \[\sqrt{y^{4}} = y^{4*\frac{1}{2}} = y^{2}\] The \(\sqrt{y}\) part cannot be simplified. Put it all together and we have \(9y^{2}\sqrt{y}\)
Bananas1234
  • Bananas1234
i think i understand that, Thank you!
anonymous
  • anonymous
Of course :)

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