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Bananas1234

  • one year ago

Simplify completely: square root of 81y^5

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  1. anonymous
    • one year ago
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    59049

  2. Bananas1234
    • one year ago
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    i dont think that is what i need sorry.

  3. Bananas1234
    • one year ago
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    options: A. 9y^2 square root y B. 3y^2 C. 3y^2 square root 2y D. 9y square root y

  4. Bananas1234
    • one year ago
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    ok

  5. Bananas1234
    • one year ago
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    why?

  6. Bananas1234
    • one year ago
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    ok i think that makes sense

  7. Bananas1234
    • one year ago
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    ok thanks!

  8. pooja195
    • one year ago
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    Whats the square root of 81?

  9. Bananas1234
    • one year ago
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    9

  10. pooja195
    • one year ago
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    good \[\huge~9*(y*y*y*y*y)\]

  11. anonymous
    • one year ago
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    \[\sqrt{81y^{5}} = \sqrt{81}*\sqrt{y^{4}}*\sqrt{y}\] You can think of it like this, which seems to be the approach of pooja above. Good luck :)

  12. Bananas1234
    • one year ago
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    9y

  13. Bananas1234
    • one year ago
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    9y square root y?

  14. Bananas1234
    • one year ago
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    @pooja195

  15. pooja195
    • one year ago
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    I agree with that. @Concentrationalizing is it right though? :/

  16. anonymous
    • one year ago
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    Well, given \[\sqrt{81y^{5}} = \sqrt{81} * \sqrt{y^{4}} * \sqrt{y}\] \(\sqrt{81} = 9\) For the \(\sqrt{y^{4}}\) part, if we think of the square root as being an exponent of 1/2, we have: \[\sqrt{y^{4}} = y^{4*\frac{1}{2}} = y^{2}\] The \(\sqrt{y}\) part cannot be simplified. Put it all together and we have \(9y^{2}\sqrt{y}\)

  17. Bananas1234
    • one year ago
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    i think i understand that, Thank you!

  18. anonymous
    • one year ago
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    Of course :)

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