anonymous
  • anonymous
q+ 4 q ------- + --------- = 2 q−1 q+1 show all work please
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
johnweldon1993
  • johnweldon1993
First we need a common denominator to add these fractions...what would that be?
anonymous
  • anonymous
would it be (q-1)(q+10) ??
johnweldon1993
  • johnweldon1993
Can I assume that 10 was a typo for 1?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
oops yeah it was
johnweldon1993
  • johnweldon1993
No problem, just want to make sure you got it :) \[\large \frac{(q+4)(q+1)}{(q-1)(q+1)} + \frac{q(q-1)}{(q-1)(q+1)} = 2\] Do you see how I got that with the common denominator?
anonymous
  • anonymous
yup! so now would it be q^2+q+4q+4+q^2-q = 2q+2 +2q - 2 right ?
johnweldon1993
  • johnweldon1993
Not quite! \[\large \frac{q^2 + 5q + 4 + q^2 - q}{(q-1)(q+1)} = 2\] \[\large q^2 + 5q + 4 + q^2 - q = 2\color\red{(q-1)(q+1)}\] \[\large (q-1)(q+1) = q^2 - 1\] so \[\large 2q^2 + 4q + 4 = 2q^2 - 2\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.