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Babynini

  • one year ago

Halp.

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  1. Babynini
    • one year ago
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  2. Babynini
    • one year ago
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    @zepdrix

  3. Babynini
    • one year ago
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    can you help? :)

  4. zepdrix
    • one year ago
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    AHHHH I'm too tiredddddd -_- what's going on now? are the ones you filled in already, correct? you think so?

  5. Babynini
    • one year ago
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    Yeah I think they're correct, but not for sure. aww i'm sorry you're tired D:

  6. zepdrix
    • one year ago
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    What is c..?

  7. Babynini
    • one year ago
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    c^2=a^2+b^2 c^2=36+64 oh..so 10

  8. zepdrix
    • one year ago
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    o, ok that looks better

  9. zepdrix
    • one year ago
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    \[\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-6,0),\qquad F_2=(6,0)\]So use your distance formula, ya?

  10. Babynini
    • one year ago
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    we can just use the p point like that?

  11. Babynini
    • one year ago
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    how do we use the distance formula here? :o

  12. zepdrix
    • one year ago
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    \[\Large\rm d(P,F_1)=\sqrt{(10--6)^2+\left(\frac{32}{3}-0\right)^2}\]ya? :d

  13. zepdrix
    • one year ago
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    Shouldn't the focus points be related to the c values? Hmm sec, reading up on some of this stuff >.<

  14. Babynini
    • one year ago
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    \[\sqrt{256+\frac{ 1024 }{ 9 }}\]

  15. Babynini
    • one year ago
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    ?

  16. Babynini
    • one year ago
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    err, dangit. Yeah I think. So it would be f1= (-10,0) f2=(10,0)

  17. Babynini
    • one year ago
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    so that changes this next part we just did. oopsies.

  18. zepdrix
    • one year ago
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    oh true :3 heh

  19. Babynini
    • one year ago
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    soo I think d(p, f1) = 68

  20. zepdrix
    • one year ago
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    \[\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-10,0),\qquad F_2=(10,0)\]Really? Hmm I'm getting something more like this,\[\Large\rm d(P,F_1)=\sqrt{(10--10)^2+\left(\frac{32}{3}-0\right)^2}\approx 22.7\]

  21. Babynini
    • one year ago
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    \[=\sqrt{(10+10)^2+(\frac{ 32 }{ 3 }-0)^2}\] \[\sqrt{400+\frac{ 1024 }{ 9 }}\] Put 400/9 then add them up and apply sq root = 68

  22. Babynini
    • one year ago
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    I messed up somewhere really bad, yeah? o.o

  23. zepdrix
    • one year ago
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    \[\Large\rm =\sqrt{400+113.8}=\sqrt{513.8}\approx 22.7\]Still not sure how you're getting 68 :) lol

  24. zepdrix
    • one year ago
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    Oh oh oh i see what You did, no no no. not 400/9 you have to multiply the top by 9 as well if u want to do it that way. 400 = (400*9)/9 = 3600/9

  25. Babynini
    • one year ago
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    yeah yeah I thought i did that :o

  26. zepdrix
    • one year ago
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    that mistake would have given you a number smaller than 22.7 though lol so i'm not sure what's going on ;0

  27. Babynini
    • one year ago
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    lol me neither. Ah well. moving on then xD

  28. Babynini
    • one year ago
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    erm so it says put exact interger. but the answer is 22.7 should i round it to 23 do you think?

  29. zepdrix
    • one year ago
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    Oh it says exact? Ok then uhhh

  30. Babynini
    • one year ago
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    oh sorry, sorry. it says "exact interger, fraction, or decimal"

  31. Babynini
    • one year ago
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    so that would be.. 3 numbers after the decimal point? o.0

  32. zepdrix
    • one year ago
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    \[\Large\rm d=\sqrt{\frac{3600}{9}+\frac{1024}{9}}=\frac{68}{3}\]Is that where the 68 was coming from? 0_o

  33. Babynini
    • one year ago
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    oh! there it is xD

  34. Babynini
    • one year ago
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    I completely forgot the 3 lol

  35. zepdrix
    • one year ago
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    how bout the other distance? :)

  36. Babynini
    • one year ago
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    would that answer be 22.666? or just two 6's?

  37. Babynini
    • one year ago
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    the other distance = 10.66?

  38. zepdrix
    • one year ago
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    68/3 is a better form of the solution. if you want a decimal with three places though, it would be 22.667

  39. zepdrix
    • one year ago
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    yes, the other distance is 32/3 :)

  40. zepdrix
    • one year ago
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    or 22.67 for two decimals

  41. Babynini
    • one year ago
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    ee the feeling of accomplishment haha yay! I'm going to try the fraction form first.

  42. Babynini
    • one year ago
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    last box!

  43. zepdrix
    • one year ago
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    \[\Large\rm \frac{68}{3}-\frac{32}{3}=?\]Fractions seem better. Makes this last step easier.

  44. Babynini
    • one year ago
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    36/3!

  45. Babynini
    • one year ago
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    :P

  46. zepdrix
    • one year ago
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    36 over 3 factorial? :o no that can't be right. jk :x hehehe

  47. Babynini
    • one year ago
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    noooo =.= haha it's 12 then xD

  48. zepdrix
    • one year ago
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    does 12 fit the form of 2(a)? where a=6?

  49. Babynini
    • one year ago
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    naaaah

  50. Babynini
    • one year ago
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    jk, yes

  51. zepdrix
    • one year ago
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    12 = 2(6) yayyy you did it \c:/ good job!

  52. Babynini
    • one year ago
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    wait so in that last box I put 12 again?

  53. Babynini
    • one year ago
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    no..it would be 6 in that box

  54. zepdrix
    • one year ago
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    ya 6 :O

  55. Babynini
    • one year ago
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    lol I was like WAIT that doesn't make sense xD yaya *we* did it!! :) ty ty

  56. Babynini
    • one year ago
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    ook let's see if it's all correct.

  57. Babynini
    • one year ago
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    yep yep it's all correct :*

  58. zepdrix
    • one year ago
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    yay \c:/

  59. Babynini
    • one year ago
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    want to help with another one? though it is quitee extensive

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