## Babynini one year ago Halp.

1. Babynini

2. Babynini

@zepdrix

3. Babynini

can you help? :)

4. zepdrix

AHHHH I'm too tiredddddd -_- what's going on now? are the ones you filled in already, correct? you think so?

5. Babynini

Yeah I think they're correct, but not for sure. aww i'm sorry you're tired D:

6. zepdrix

What is c..?

7. Babynini

c^2=a^2+b^2 c^2=36+64 oh..so 10

8. zepdrix

o, ok that looks better

9. zepdrix

$\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-6,0),\qquad F_2=(6,0)$So use your distance formula, ya?

10. Babynini

we can just use the p point like that?

11. Babynini

how do we use the distance formula here? :o

12. zepdrix

$\Large\rm d(P,F_1)=\sqrt{(10--6)^2+\left(\frac{32}{3}-0\right)^2}$ya? :d

13. zepdrix

Shouldn't the focus points be related to the c values? Hmm sec, reading up on some of this stuff >.<

14. Babynini

$\sqrt{256+\frac{ 1024 }{ 9 }}$

15. Babynini

?

16. Babynini

err, dangit. Yeah I think. So it would be f1= (-10,0) f2=(10,0)

17. Babynini

so that changes this next part we just did. oopsies.

18. zepdrix

oh true :3 heh

19. Babynini

soo I think d(p, f1) = 68

20. zepdrix

$\Large\rm P=\left(10,\frac{32}{3}\right),\qquad F_1=(-10,0),\qquad F_2=(10,0)$Really? Hmm I'm getting something more like this,$\Large\rm d(P,F_1)=\sqrt{(10--10)^2+\left(\frac{32}{3}-0\right)^2}\approx 22.7$

21. Babynini

$=\sqrt{(10+10)^2+(\frac{ 32 }{ 3 }-0)^2}$ $\sqrt{400+\frac{ 1024 }{ 9 }}$ Put 400/9 then add them up and apply sq root = 68

22. Babynini

I messed up somewhere really bad, yeah? o.o

23. zepdrix

$\Large\rm =\sqrt{400+113.8}=\sqrt{513.8}\approx 22.7$Still not sure how you're getting 68 :) lol

24. zepdrix

Oh oh oh i see what You did, no no no. not 400/9 you have to multiply the top by 9 as well if u want to do it that way. 400 = (400*9)/9 = 3600/9

25. Babynini

yeah yeah I thought i did that :o

26. zepdrix

that mistake would have given you a number smaller than 22.7 though lol so i'm not sure what's going on ;0

27. Babynini

lol me neither. Ah well. moving on then xD

28. Babynini

erm so it says put exact interger. but the answer is 22.7 should i round it to 23 do you think?

29. zepdrix

Oh it says exact? Ok then uhhh

30. Babynini

oh sorry, sorry. it says "exact interger, fraction, or decimal"

31. Babynini

so that would be.. 3 numbers after the decimal point? o.0

32. zepdrix

$\Large\rm d=\sqrt{\frac{3600}{9}+\frac{1024}{9}}=\frac{68}{3}$Is that where the 68 was coming from? 0_o

33. Babynini

oh! there it is xD

34. Babynini

I completely forgot the 3 lol

35. zepdrix

how bout the other distance? :)

36. Babynini

would that answer be 22.666? or just two 6's?

37. Babynini

the other distance = 10.66?

38. zepdrix

68/3 is a better form of the solution. if you want a decimal with three places though, it would be 22.667

39. zepdrix

yes, the other distance is 32/3 :)

40. zepdrix

or 22.67 for two decimals

41. Babynini

ee the feeling of accomplishment haha yay! I'm going to try the fraction form first.

42. Babynini

last box!

43. zepdrix

$\Large\rm \frac{68}{3}-\frac{32}{3}=?$Fractions seem better. Makes this last step easier.

44. Babynini

36/3!

45. Babynini

:P

46. zepdrix

36 over 3 factorial? :o no that can't be right. jk :x hehehe

47. Babynini

noooo =.= haha it's 12 then xD

48. zepdrix

does 12 fit the form of 2(a)? where a=6?

49. Babynini

naaaah

50. Babynini

jk, yes

51. zepdrix

12 = 2(6) yayyy you did it \c:/ good job!

52. Babynini

wait so in that last box I put 12 again?

53. Babynini

no..it would be 6 in that box

54. zepdrix

ya 6 :O

55. Babynini

lol I was like WAIT that doesn't make sense xD yaya *we* did it!! :) ty ty

56. Babynini

ook let's see if it's all correct.

57. Babynini

yep yep it's all correct :*

58. zepdrix

yay \c:/

59. Babynini

want to help with another one? though it is quitee extensive