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Bananas1234

  • one year ago

Divide and simplify: (a-4)(a + 3)/a^2 - 2 divided by 2(a-4)/(a + 3)(a-1)

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  1. Bananas1234
    • one year ago
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    @jim_thompson5910

  2. Bananas1234
    • one year ago
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    @robtobey

  3. jim_thompson5910
    • one year ago
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    When you divide two fractions, you will flip the second fraction and multiply Example: 1/2 divided by 3/4 = 1/2 times 4/3 So in this case, it means \[\Large \frac{(a-4)(a+3)}{a^2-2} \div \frac{2(a-4)}{(a+3)(a-1)}\] turns into \[\Large \frac{(a-4)(a+3)}{a^2-2} \times \frac{(a+3)(a-1)}{2(a-4)}\]

  4. jim_thompson5910
    • one year ago
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    I'll let you simplify

  5. Bananas1234
    • one year ago
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    im not sure i know how to simplify can you walk me through it? @jim_thompson5910

  6. jim_thompson5910
    • one year ago
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    well I can only see one pair of terms cancelling. Can you see it too?

  7. Bananas1234
    • one year ago
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    the 2 (a + 3)

  8. jim_thompson5910
    • one year ago
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    no, the "(a-4)" \[\Large \frac{(a-4)(a+3)}{a^2-2} \times \frac{(a+3)(a-1)}{2(a-4)}\] \[\Large \frac{{\color{red}{(a-4)}}(a+3)}{a^2-2} \times \frac{(a+3)(a-1)}{2{\color{red}{(a-4)}}}\] \[\Large \frac{{\color{red}{\cancel{(a-4)}}}(a+3)}{a^2-2} \times \frac{(a+3)(a-1)}{2{\color{red}{\cancel{(a-4)}}}}\] \[\Large \frac{a+3}{a^2-2} \times \frac{(a+3)(a-1)}{2}\]

  9. Bananas1234
    • one year ago
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    i see

  10. jim_thompson5910
    • one year ago
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    now multiply straight across

  11. Bananas1234
    • one year ago
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    a+3^2/2a?

  12. jim_thompson5910
    • one year ago
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    more like \[\Large \frac{a+3}{a^2-2} \times \frac{(a+3)(a-1)}{2}\] \[\Large \frac{(a+3)(a+3)(a-1)}{2(a^2-2)}\] \[\Large \frac{(a+3)^2(a-1)}{2(a^2-2)}\]

  13. Bananas1234
    • one year ago
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    a+3^2/2?

  14. jim_thompson5910
    • one year ago
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    you can't cancel anything else

  15. Bananas1234
    • one year ago
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    so thats it? :)

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