A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

I apologize, I need a little bit of help... I am thinking that it is D. Determine which trigonometric function to use to solve for the hypotenuse. Then, solve for the length of the hypotneuse. b = 9 A = 55.8 a. cosine, .062 c. sine, 16.0 b. sine, 10.8 d. cosine, 16.0

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. geerky42
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes D is correct.

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[c=9 \sec (55.8 {}^{\circ})=16.0119 \]

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @robtobey Are you saying that it is C? (I am sorry, I'm a little confused.)

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    c/b = sec(A) c = b sec(A) This method is not listed in the answer stack,

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh, I see.

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.