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AmTran_Bus
 one year ago
Inverse problem?
AmTran_Bus
 one year ago
Inverse problem?

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0I am willing to work it out, just need help.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0The inverse is y=x^2+4, right?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Hum. Well, this is online, but let me reference a book.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Maybe this?dw:1433387173701:dw

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2Looks right, but seem useless, since we can just use g(x) to derivative with.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2We know \[g(x) =f^{1}(x)= x^2+4\]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2well, you should be able to handle the rest.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0I mean, do you just plug it in?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2well, take derivative of g(x), then plug in

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2\(g(x) = x^2+4\) So \(g'(x) = 2x\) Now plug in \(x=4\); \[g'(4) = \boxed{8}\]

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Hey @geerky42, would I do this the exact same way?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Its inverse is y= 2+x^2+tan(pi x/2)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2That's exactly same function as original function.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2its inverse should have arctan

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me continue on then? I haven't really studied that in this context.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2Did you find inverse? You can swap x and y to each other, then isolate tan(...)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2from there, take arctan.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Eek man, why is this one so hard?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2Gee didn't realize that finding inverse would be hard lol...

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2@ganeshie8 Can you help?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1I don't seem to remember the inverse derivative formula... deriving it is easy we knw that \[\large f(f^{1}(x)) = x\] differentiating both sides gives \[\large f'(f^{1}(x)){f^{1}}'(x)=1 \] \[\large {f^{1}}'(x) = \dfrac{1}{ f'(f^{1}(x))}\]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2Hmm. What is \(f(0)\)? @AmTran_Bus

geerky42
 one year ago
Best ResponseYou've already chosen the best response.2It seems that we need to use reasoning here.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0I think we are maybe overthinking. Look at the choices they give as answers.
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