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anonymous
 one year ago
find the solutions to the system
y=x^22x2
y=4x+5
a.(1.1) (7.23)
b.(1.1) (7,33)
c.(1,33) (7,1)
d. no solution
anonymous
 one year ago
find the solutions to the system y=x^22x2 y=4x+5 a.(1.1) (7.23) b.(1.1) (7,33) c.(1,33) (7,1) d. no solution

This Question is Closed

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well since both equations are equal to, you can equate them \[4x + 5 = x^2 2x 2\] which can be rewritten as \[x^2  6x  7 = 0\] now solve for x by factoring

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0just factor as the gentle man said!

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0\[x^26x7=(x+1)(x7)=0\] \[x+1=0~~or~~x7=0\] and go on

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0once you get the x you plug it in one equation and look for y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know how to factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@xapproachesinfinity

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Then use the formula for the solutions of the quadratic \(ax^2 + bx + c = 0\): \[x = \frac{b\pm\sqrt{b^24ac}}{2a}\] Your quadratic is \[x^26x+7=0\]so you have \(a=1,\ b=6,\ c=7\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im still really confused

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Okay, you'll have to do a better job of describing your confusion. I gave you a formula and 3 numbers to plug into the formula. Are you able to do that?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0if you are hoping that I will just give you the answer instead of helping you through the process of finding it yourself, today is not your lucky day.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0If you can't do this algebraically then you can graph the curves use this site https://www.desmos.com/calculator then find where the 2 curves intersect

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm using this website currently it's really helpful, i didn't even think of that, thank you!

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0It is troubling to hear you say that you haven't learned this, when you clearly are expected to know it...this is all material you will use many, many times in the future, except perhaps in the unlikely case this is the last math class you ever take. Do you have a live teacher to ask for help on this material?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0I agree with @whpalmer4 , I'm sure this work on solving simultaneous equations would be covered in your notes the original method I posted is basically substitution.... then you would need to solve the quadratic equation... anyway, the graphing method will work...
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