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gabbyalicorn

  • one year ago

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

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  1. gabbyalicorn
    • one year ago
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    @BrainSmart

  2. gabbyalicorn
    • one year ago
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    @jabez177 @jim_thompson5910

  3. gabbyalicorn
    • one year ago
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    @Whitemonsterbunny17 @geerky42

  4. gabbyalicorn
    • one year ago
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    2/26 ?

  5. jabez177
    • one year ago
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    I'm not too sure on this one...

  6. gabbyalicorn
    • one year ago
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    can you tag some other peopl please, i tagged all the people that I know that are good in math.

  7. jabez177
    • one year ago
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    Except one... @Pooja195 :P

  8. gabbyalicorn
    • one year ago
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    Okay, thanks

  9. gabbyalicorn
    • one year ago
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    @Black_ninja123

  10. YoungStudier
    • one year ago
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    I had this question! O_O

  11. Black_ninja123
    • one year ago
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    Any answer choices?

  12. gabbyalicorn
    • one year ago
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    nope

  13. gabbyalicorn
    • one year ago
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    P(red and yellow) ≈ (blank space) %

  14. Zarkon
    • one year ago
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    \[P(R_1\cap Y_2)=P(Y_2|R_1)P(R_1)\]

  15. gabbyalicorn
    • one year ago
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    ?.?

  16. Black_ninja123
    • one year ago
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    what is that?

  17. gabbyalicorn
    • one year ago
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    im not even that far in math to know that.. im in midddle schoool not high school..

  18. Zarkon
    • one year ago
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    P(red on first and yellow on second)=P(yellow on 2nd given red on first)*P(red on first)

  19. Black_ninja123
    • one year ago
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    The answer is 26% because 14/26*12/25=84/325 84/325 as a percent is 25.84%

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