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Have you looked at the left and right limit to x=0?

No, I don't understand how this specific example works

x<0 means to the left of x=0
x>0 means to the right of x=0

use the functions for x<0
and for x>0
to find the left and right limit

|dw:1433390979523:dw|

Okay, so since there is the x->0 does that mean I use |-4-x| ?

| -4-0 | = 4
5(0) - 8 = -8
correct? so they are different?

and yes to your question 4 is not -8

wow thank you for your help!! for this one, is it 8?

did you find left and right limit?

except we looked around 0 since we had x approaching 0

we are not concerned at what happens at x=1

anyways you can conclude since 0 isn't 8
the limit __________?

Oh alright, Yes the limit does not exist

yep

thanks so much, these are just hard for me to understand

like if you want to explain what is hard about it I can try to explain

or like what you don't get about what I have said

when evaluating limits we aren't concerned at what happens at x=a
but what happens around x=a

|dw:1433392350183:dw|

|dw:1433392388087:dw|
this is where f is to the left of x=a

notice the y values are approaches k

|dw:1433392435150:dw|

that is the left limit of x=a

now to the right of x=a
you want to use the right piece

|dw:1433392480605:dw|

those y values are approaching m

\[\lim_{x \rightarrow a^-}f(x)=k \\ \lim_{x \rightarrow a^+}f(x)=m\]

|dw:1433392571595:dw|
anyways i hope that is more clear