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Babynini

  • one year ago

Vectors, please check :)

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  1. Babynini
    • one year ago
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    A few simple questions! u= <-2,4> v=5i-3i 1) find 6u-v = <-17,21> 2) fine a unit vector in the direction of v this one i'm ont sure about 3) graph u, v, and u-v with initial points of origin. again, i have an idea but im not sure

  2. ganeshie8
    • one year ago
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    look there is a typo ``` v=5i-3i ```

  3. Babynini
    • one year ago
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    sowire v= 5i-3j

  4. ganeshie8
    • one year ago
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    6*4 - (-3) = ?

  5. Babynini
    • one year ago
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    27

  6. Babynini
    • one year ago
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    why those numbers?

  7. ganeshie8
    • one year ago
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    u= <-2, 4> v=5i-3j = <5, -3> 6u - v = ?

  8. Babynini
    • one year ago
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    <-17,21>

  9. ganeshie8
    • one year ago
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    can you show work for how you got 21 ?

  10. Babynini
    • one year ago
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    6u = <-12,24> v= <5,-3> (-12-5), (24-3) = <-17,21>

  11. ganeshie8
    • one year ago
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    check again

  12. ganeshie8
    • one year ago
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    is it 24-3 or 24-(-3) ?

  13. Babynini
    • one year ago
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    ooh right rigt.

  14. Babynini
    • one year ago
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    soo.. <-17,25> ?

  15. Babynini
    • one year ago
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    lol sorry, *27

  16. ganeshie8
    • one year ago
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    yes

  17. Babynini
    • one year ago
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    fabulous :)

  18. Babynini
    • one year ago
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    part b then

  19. ganeshie8
    • one year ago
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    what do u know about unit vector ?

  20. Babynini
    • one year ago
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    er, is this where I use cos and sin?

  21. Babynini
    • one year ago
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    or multiplying by scalar?

  22. Babynini
    • one year ago
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    Idk :/

  23. Babynini
    • one year ago
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    It's the angle formed by the vector and x.

  24. ganeshie8
    • one year ago
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    unit vector is just a vector whose magnitude is 1 and points in the same direction

  25. ganeshie8
    • one year ago
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    what is the magnitude of vector v ?

  26. Babynini
    • one year ago
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    er \[\sqrt{25+9}\]

  27. ganeshie8
    • one year ago
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    yes what do you need to do to make it 1 ?

  28. Babynini
    • one year ago
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    What do you mean?

  29. ganeshie8
    • one year ago
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    what do you need to do to \(\sqrt{25+9}\) to make it \(1\) ?

  30. ganeshie8
    • one year ago
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    dividing by \(\sqrt{25+9}\) produces \(1\), yes ?

  31. Babynini
    • one year ago
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    yeah dividing it by itself

  32. ganeshie8
    • one year ago
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    so the unit vector is simply : \[\large \dfrac{v}{\|v\|}\]

  33. ganeshie8
    • one year ago
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    dividing the original vector by its magnitude gives the unit vector

  34. Babynini
    • one year ago
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    \[\frac{ 5i -3j}{ \sqrt{34} }\]

  35. Babynini
    • one year ago
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    ?

  36. ganeshie8
    • one year ago
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    Yes thats the unit vector in the direction of \(v\)

  37. Babynini
    • one year ago
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    so that would be the final answer? :)

  38. ganeshie8
    • one year ago
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    yes

  39. Babynini
    • one year ago
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    yay! Part c then ^-^

  40. ganeshie8
    • one year ago
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    graph the vectors

  41. ganeshie8
    • one year ago
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    |dw:1433398194050:dw|

  42. ganeshie8
    • one year ago
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    To graph the vector u= <-2,4> first plot the point (-2, 4) and draw an arrow from (0,0) to (-2,4)

  43. Babynini
    • one year ago
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    |dw:1433398294843:dw|

  44. Babynini
    • one year ago
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    (-7,7) isn't on the graph :P

  45. ganeshie8
    • one year ago
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    |dw:1433398431757:dw|

  46. ganeshie8
    • one year ago
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    yeah u-v = <-7, 7> is not on this graph but i see you get how to draw the vectors

  47. ganeshie8
    • one year ago
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    don't forget to put arrow at the final point

  48. Babynini
    • one year ago
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    okies! thanks :)

  49. ganeshie8
    • one year ago
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    np

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