A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Please help one question!
Use graphs and tables to find the limit and identify any vertical asymptotes of the function:
lim x>2, 1/((x2)^2)
I know that it is +infinite and the asymptote is 2 but i dont know how to explain it
anonymous
 one year ago
Please help one question! Use graphs and tables to find the limit and identify any vertical asymptotes of the function: lim x>2, 1/((x2)^2) I know that it is +infinite and the asymptote is 2 but i dont know how to explain it

This Question is Closed

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1I guess you could say that as you approach 2 from the left it shoots up to infinity. And being 2 would leave you with an undefined value. The limit coming from the right to 2 would also approach infinity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But i dont know how to explain why it does that. Like I need to explain how I got my answer but I dont know how to explain it.

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1You could do what the instructions said and use a graph and table. Visually speaking, you can see it starts shooting up as it approaches 2. Mathematically, if you look at a table, the values start increasing as well. \(\large \lim_{x\rightarrow1.9} f(x)=100\) \(\large \lim_{x\rightarrow1.99} f(x)=10000\) \(\large \lim_{x\rightarrow1.999} f(x)=1000000\) \(\large \lim_{x\rightarrow1.99999} f(x)=+\infty\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand that part thank you, but what part of the equation shows the graph going up? I know that x > 2 shows us the vertical asymptote of 2, but how does 1/((x2)^2) show it going up?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Are you asking how to clarify it is increasing?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1plug in values? x=1, \(f(x)=\frac{1}{(x2)^2} ===> f(1)\frac{1}{(12)^2}=\frac{1}{1^2}=1\) x=1.5 \(f(x)=\frac{1}{(x2)^2} ===> f(1.5)\frac{1}{(1.52)^2}=\frac{1}{.5^2}=4\) x=1.75 \(f(x)=\frac{1}{(x2)^2} ===> f(1.75)\frac{1}{(1.752)^2}=\frac{1}{.25^2}=16\) x=1.9 \(f(x)=\frac{1}{(x2)^2} ===> f(1)\frac{1.9}{(1.92)^2}=\frac{1}{.1^2}=100\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Refer to the attached plot.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.