http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%207.37.12%20PM_zpseia5o480.png.html
I need help number 18 and 20
please check number 18 did
P(A and B)=P(A) X P(B)
P(A and B) / P(B)= P(A)
= 0.15/0.6
= 1/4 ?

- anonymous

- chestercat

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- phi

I would say
\[ P(B|A)= \frac{P(A \cap B)}{P(A)} \]
so
\[ P(A)= \frac{P(A \cap B)}{P(B|A)} \]
with P(B|A)= 0.6 and P(A \(\cap\) B) =0.15
from which you get P(A)= 0.25

- anonymous

ok,Thanks, can you do number 20?

- phi

For Q20
there are 20 marbles , 9 of them red. so 9/20 chance of choosing a red marble on the first pick. If you put the marble back in, then you will have 9/20 chance of picking red on the second pick, and 9/20 on the third. thus
\[ \left(\frac{9}{20}\right)^3 \]

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## More answers

- phi

If you do not replace the marble, then the chance of picking a red marble on the first pick is 9/20, on the second 8/19 and on the third 7/18
thus
\[ \left( \frac{9}{20}\right)\left( \frac{8}{19}\right)\left( \frac{7}{18}\right) \]

- phi

for part A, each time you pick is an independent event (because we put the marble back in the bag). That means each pick should be 9/20
and for multiple independent events, you multiply the individual probability to find the probability of all the events occurring.

- anonymous

thanks , can you have me some more ?

- anonymous

http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%207.37.25%20PM_zpsthipwake.png.html

- phi

ok

- anonymous

this one I no idea

- phi

for event A, you count up the number of tiles that are consonants
(the problem is y is sometimes a vowel e.g. fly, by, dry, or as a consonant e.g.
you, yell, young, ...)
not sure how to handle that.

- phi

and of course for B, first count the number of tiles that are vowels.

- anonymous

let me know if later you can solve , I need help if you can check my work it correct

- anonymous

can you check my answer ?

- phi

Let's assume y is only a consonant. then there are 42 vowels, 2 blanks, 56 consonants
the chance of choosing a consonant on the first draw is 56/100
and the chance of choosing a vowel on the 2nd draw is 42/99

- phi

and we multiply
(56/100)*(42/99)

- anonymous

http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%205.56.17%20PM_zpstctblc9x.png.html
\[\frac{ 1 }{6 }\] \[\frac{ 1 }{ 6 } . of .60 = 10 ?\]

- phi

yes, and the 4 spot came up 10 times

- anonymous

ok, nexthttp://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%205.56.23%20PM_zpscjpwjnoy.png
\[\frac{ 1 }{ 5 }\times30?\]

- phi

yes, so the black marble.

- anonymous

thanks,nexthttp://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%205.56.08%20PM_zpszlf9z9b0.png
\[\frac{ 179 }{ 2237 }=0.0800\]
0.0800 x 100= 8% ?

- phi

I would leave the answer as 0.08

- anonymous

thankshttp://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%205.56.29%20PM_zpsfhmscrjx.png.html
\[\frac{ 526 }{ 2392 }?\]

- phi

yes

- anonymous

http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%206.19.45%20PM_zpshyvuxfv0.png
\[5<30 <80<90\]

- phi

your picture of the weather does not match up with 9/12000

- anonymous

let me check

- phi

for the weather question I think they want you to order A , B, C , D from least to most likely

- anonymous

ok,
http://i296.photobucket.com/albums/mm168/ontoonex99/Screen%20Shot%202015-06-02%20at%206.20.56%20PM_zpsldqx0cs1.png
\[\frac{ 9 }{ 12000 }?\]

- phi

9/1200 (not 12000)
and expected number of defects is 9/1200 * 15000

- anonymous

\[\frac{ 9 }{ 1200 }\times1500?\]

- phi

yes

- anonymous

let go back to number 22
D

- phi

chance of rain on Fri is 5%, so chance of no rain is 95%
i.e. D has prob= 95%

- phi

and they want the order smallest to biggest. D will be the biggest chance.

- phi

what numbers do you get for A, B , C and D ?
for A and C, read off the number from the chart
for B and D, do 100 - what is on the chart.

- phi

I get A 80, B 70, C 90, D 95

- anonymous

thanks you . Take me so long ti fix out ,http://s296.photobucket.com/user/ontoonex99/media/Screen%20Shot%202015-06-02%20at%207.35.09%20PM_zpse2zctvy9.png.html
3) Dependent
4) independent

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