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anonymous

  • one year ago

What is the limit as x approaches infinity of (ln(x+2)-ln(x+1))?

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  1. ParthKohli
    • one year ago
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    \[\ln\left(\dfrac{x+2}{x+1}\right)\]\[= \ln \left(1 + \frac{1}{x+1}\right)\]Does that ring a bell? :)

  2. anonymous
    • one year ago
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    Before you go ahead and answer the question, you must see whether the logarithmic function exist or not. By setting the function within the log to greater than 0. e.g x + 2 > 0 etc In this question it does ^^

  3. anonymous
    • one year ago
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    The \[\lim_{x \rightarrow \infty} (\ln(x+2)-\ln(x+1))\] The value for x is 0 as it approaches infinity in this question. Why? As you substitute the value of infinity into this question, large values inside of a logarithmic over a large value in a logarithmic, is almost zero. So essential it is 0

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