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anonymous
 one year ago
What is the limit as x approaches infinity of (ln(x+2)ln(x+1))?
anonymous
 one year ago
What is the limit as x approaches infinity of (ln(x+2)ln(x+1))?

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ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2\[\ln\left(\dfrac{x+2}{x+1}\right)\]\[= \ln \left(1 + \frac{1}{x+1}\right)\]Does that ring a bell? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Before you go ahead and answer the question, you must see whether the logarithmic function exist or not. By setting the function within the log to greater than 0. e.g x + 2 > 0 etc In this question it does ^^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The \[\lim_{x \rightarrow \infty} (\ln(x+2)\ln(x+1))\] The value for x is 0 as it approaches infinity in this question. Why? As you substitute the value of infinity into this question, large values inside of a logarithmic over a large value in a logarithmic, is almost zero. So essential it is 0
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