-2x² - 7 = 4x Where are a, b, and c in this equation? How do I solve this with the quadratic equation?

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-2x² - 7 = 4x Where are a, b, and c in this equation? How do I solve this with the quadratic equation?

Mathematics
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remember, a standard quadratic equation is always in this form: \(a^{2}x+bx+c\) so you're going to need to manipulate this equation to set it to this formula
Is a 2? Is b 4? Is C 7?
we have this equation: -2x² - 7 = 4x We need to rearrange it so that the x² part is positive. Therefore take the "-2x² - 7" to the other side of the equals sign and we get: -2x² - 7 = 4x 0 = 2x² + 4x +7 Standard form is : ax² + bx + c = 0 Therefore match it up with your equation and we get: a = 2, b = 4 , c = 7 Which you said.. so you're correct ^_^!

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How do I solve this?
use this formula\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
yeah use the quadratic formula (as stated by surjithayer) to solve for x :)
1.58?
not quite we know a = 2, b = 4 and c = 7 plug these values into the quadratic formula: |dw:1433428335720:dw|
note: we cannot square root a negative number. Therefore, there will be no solution... What i mean by this is that in this part here: |dw:1433428482052:dw| And we can't square root -40. Therefore x will have no solution
WHAT?!
I thought that when the numerator says "\[\pm\]", you were supposed to change the number to a positive whenever you square rooted it.
hmm.. the plus and minus sign, means that you can get TWO solutions... for x. You want to concentrate on what is happening INSIDE the square root sign: |dw:1433430575846:dw| plug it into the calculator and tell me if you get an answer :)
you should get a math error. Why? Because we can't square root a negative number.

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