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anonymous
 one year ago
Find the exact value of sin(a+b):
If sina=3/5, 0< a< pi/2; cos B= 2 root 5/5, =pi/2<B<o
anonymous
 one year ago
Find the exact value of sin(a+b): If sina=3/5, 0< a< pi/2; cos B= 2 root 5/5, =pi/2<B<o

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butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0hmm.. sin ( a+ b) = sina cosb + sinb cosa We are given: sina = 3/5 , cos b = 2 root 5/5 So draw out two triangles: dw:1433425889828:dw

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0sin (a + b ) = sina cosb + sinb cosa We know sina 3/5 , cosb = 2sqrt5/5 So find sinb and cosa from the triangles and then plug it into the formula in the first line :)

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0what don't you understand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you find sinb amd cos a?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0look at the triangles. Sin = opposite/ hypotenuse Cos = adjacent/ hypotenuse dw:1433427282198:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so how did you get those Triangles in the beginning?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0sin = opposite / hypotenuse right? They told us that "Sina = 3/5" This means opposite side = 3 and hypotenuse = 5 Therefore you set up the right angled triangle and draw it out.. Same with cosb = 2sqrt 5/5 cos = adjacent / hypotenuse Therefore adjacent = 2sqrt 5 , hypotenuse = 5 Then draw out the right angled triangle and label the sides.
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