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HELP ASAP!!!! ANYONE!!!!!! WILL FAN AND MEDAL!!! Use the law of sines to find the missing angle of the triangle (drawing is shown below): A. 110.0 B. 153.9 C. 26.1 D. 70.0

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Other answers:

@Australopithecus can you help?
Nobody wants to help me? :(
You want to find the missing angle but there are 2 missing angles, which one do you want?
i would say C or D because it wouldnt be alot high
oh sorry I need to find the measure of angle b
angle b
Well if you find one you know the other one
according to law of sines the ratio of the single of an angle to the side opposite to the angle is equal for all pairs \[\frac{\sin(C)}{AB}=\frac{\sin(A)}{BC}=\frac{\sin(B)}{AC}\]
that 40 is angle A or is the side length?
angle a
I got D is that right?
Please I've been at this for hours I just need an answer
I think you should first calculate angle C \[\frac{\sin(C)}{19}=\frac{\sin(4)}{13}\] Use this to find sin(C) after that you can do \[\frac{\sin(B)}{AC}=\frac{\sin(40)}{13}\]\[\frac{\sin(B)}{AC}=\frac{\sin(C)}{19}\] this would be a linear equation in 2 variable once u find C then u can solve it using substitution methods
Is D right?
Idk, I haven't calculated it
*sigh* this is ridiculous.
I will show you how to solve this problem
I just need to know if d is right or not
y'know what, Nvm, I finished it. no medals for anybody
\[\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}\] |dw:1433428299531:dw| so you will have an equation set up as follows: sin(B)/b = sin(C)/19 = sin(40)/13 You will need to solve for C then remember that 180 = Angle A + Angle B + Angle C Then you can solve for angle B
yes your answer is correct sorry just woke up

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