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anonymous

  • one year ago

Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the coefficient 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x + k)(x − k)(3x + 2) k= ____________ Numerical Answers Expected! Answer for Blank 1:

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  1. anonymous
    • one year ago
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    \[6 x^3+4x^2-6x-4=2[3x^3+2x^2-3x-2]=2[(3x^3+2x^2)-1(3x+2)]\] \[=2[x^2(3x+2)-1(3x+2)]\] =?

  2. anonymous
    • one year ago
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    im sorry i really dont understand how to do any of this..

  3. amistre64
    • one year ago
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    the simplest process is to just expand the right side, and compare coefficients

  4. Loser66
    • one year ago
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    @joannaayala17 follow @amistre64, please

  5. amistre64
    • one year ago
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    as a test, lets try this: let x=0 what do we end up with?

  6. amistre64
    • one year ago
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    0+0+0-4 = 2(0+k)(0-k)(0+2)

  7. anonymous
    • one year ago
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    It's a polynomial of the form \[ax^3+bx^3+c+d\] Consider the "d" term on both the sides Now obviously on the left side this term is -4 on the right side it, it can be obtained be multiplying all constants together, note k is a constant and not a variable \[-4=2 \times k \times (-k) \times2\]

  8. anonymous
    • one year ago
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    sorry \[ax^3+bx^2+cx+d\] is what I mean

  9. anonymous
    • one year ago
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    If you're having trouble you can always expand all the parenthesis

  10. anonymous
    • one year ago
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    and then compare

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