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anonymous
 one year ago
Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the coefficient 'k' in the factored form?
6x3 + 4x2 − 6x − 4 = 2(x + k)(x − k)(3x + 2)
k= ____________
Numerical Answers Expected!
Answer for Blank 1:
anonymous
 one year ago
Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the coefficient 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x + k)(x − k)(3x + 2) k= ____________ Numerical Answers Expected! Answer for Blank 1:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[6 x^3+4x^26x4=2[3x^3+2x^23x2]=2[(3x^3+2x^2)1(3x+2)]\] \[=2[x^2(3x+2)1(3x+2)]\] =?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sorry i really dont understand how to do any of this..

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0the simplest process is to just expand the right side, and compare coefficients

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0@joannaayala17 follow @amistre64, please

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0as a test, lets try this: let x=0 what do we end up with?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.00+0+04 = 2(0+k)(0k)(0+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's a polynomial of the form \[ax^3+bx^3+c+d\] Consider the "d" term on both the sides Now obviously on the left side this term is 4 on the right side it, it can be obtained be multiplying all constants together, note k is a constant and not a variable \[4=2 \times k \times (k) \times2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry \[ax^3+bx^2+cx+d\] is what I mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you're having trouble you can always expand all the parenthesis
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