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Daltonw
 one year ago
Four polynomial functions are shown below:
f(x) = x3 + 3x2  4x  12
g(x) = x2  x  2
p(x) = x3 + 3x + 2
t(x) = x2 + x  2
Which of the following functions has 1 and 2 as its zeros?
f(x)
g(x)
p(x)
t(x)
Daltonw
 one year ago
Four polynomial functions are shown below: f(x) = x3 + 3x2  4x  12 g(x) = x2  x  2 p(x) = x3 + 3x + 2 t(x) = x2 + x  2 Which of the following functions has 1 and 2 as its zeros? f(x) g(x) p(x) t(x)

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.0test ONE BY ONE to figure out the correct one.

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0test?? you mean solve each one?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0For example: f(x) put 1 in, you have \(f(1) = (1)^3 +3(1)^24(1) 12 =6\) hence 1 is NOT a root of f(x) , therefore, f(x) is NOT the correct solution. do the same with other options.

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0ah!! i see! i don't know how to do the other ones the only one i knew how was the first on! could you maybe guide me in steps to do this next one?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0I guided you all, now your turn to show your brain.

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0well my issue is i know how to do equations with 4 number in them but i don't know what to do with ones that have 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can cancel out p(x) as all the terms are adding so a positive number like 2 will give a positive value in p(x) and it can never be 0 for positive values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try the her 3 polynomials

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0okay! what would be the first step in solving a trinomial?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Why do you need solving them?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0to this kind of problem, just plug the GIVEN solutions in. Dat sit

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0what are you seriouse??

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean? I got mad because you complicate the problem while you have a very simple way to get the answer.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0When students struggle with a simple problem, the potential they give up is so high. I don't want it. That is why I always give out the simplest way to solve the problems (if there is some and I know it)

Daltonw
 one year ago
Best ResponseYou've already chosen the best response.0okay! sorry i mad you mad. I always over complicate these things!
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