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anonymous

  • one year ago

Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

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  1. pooja195
    • one year ago
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    We need to find the slope first

  2. pooja195
    • one year ago
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    \[\huge~\frac{ y_2-y_1 }{ x_2-x_1 }\]

  3. pooja195
    • one year ago
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    (x1,y1) (x2,y2)

  4. anonymous
    • one year ago
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    3/-3

  5. anonymous
    • one year ago
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    i think?

  6. mathmate
    • one year ago
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    (x1,y1)=(-3,2) (x2,y2)=(6,-1) So (y2-y1)/(x2-x1) = (-1-2)/(6-(-3)) = ?

  7. mathmate
    • one year ago
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    It is always a good idea to write down the two points one on top of the other, as @pooja195 suggested earlier. This way, it's easier to figure out the numbers without making a mistake.

  8. anonymous
    • one year ago
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    3/-3

  9. anonymous
    • one year ago
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    wait 1/-3

  10. mathmate
    • one year ago
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    Excellent, so that's your slope, 1/-3 is the same as -1/3. Now use the point slope form to get the equation. You can use P1=(x1,y1)=(-3,2) as your point, and slope is a=-1/3. The equation is then (y-y1) = a(x-x1)

  11. anonymous
    • one year ago
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    y= 1/3 x-1?

  12. mathmate
    • one year ago
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    You are close, but got signs wrong somewhere.

  13. anonymous
    • one year ago
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    y=-1/3 x+1?

  14. mathmate
    • one year ago
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    That's it, excellent! Is everything clear?

  15. anonymous
    • one year ago
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    yes thank you so much!!

  16. mathmate
    • one year ago
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    You're welcome! @pooja195 started you off with the right foot!

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