## anonymous one year ago Find the equation of a circle that has its center at (-4, 3) and has a radius of 5. (x + 4) 2 + (y - 3) 2 = 25 (x - 4) 2 + (y - 3) 2 = 25 (x + 4) 2 + (y + 3) 2 = 25 (x - 4) 2 + (y + 3) 2 = 25

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1. Nnesha

$\huge\rm (x-h)^2 + (y-k)^2= r^2$ standard form equation of the circle where (h,k) is the center and r is radius

2. anonymous

so what do I substitute for h and k?

3. Nnesha

(h,k) is the center so given center is (-4,3) that's what you have to substitute for (h,k) :-)

4. anonymous

so -4 is h and 3 is k?

5. Nnesha

yes right

6. anonymous