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anonymous

  • one year ago

Find the equation of a circle that has its center at (-4, 3) and has a radius of 5. (x + 4) 2 + (y - 3) 2 = 25 (x - 4) 2 + (y - 3) 2 = 25 (x + 4) 2 + (y + 3) 2 = 25 (x - 4) 2 + (y + 3) 2 = 25

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  1. Nnesha
    • one year ago
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    \[\huge\rm (x-h)^2 + (y-k)^2= r^2\] standard form equation of the circle where (h,k) is the center and r is radius

  2. anonymous
    • one year ago
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    so what do I substitute for h and k?

  3. Nnesha
    • one year ago
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    (h,k) is the center so given center is (-4,3) that's what you have to substitute for (h,k) :-)

  4. anonymous
    • one year ago
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    so -4 is h and 3 is k?

  5. Nnesha
    • one year ago
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    yes right

  6. anonymous
    • one year ago
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    so the answer is a?

  7. Nnesha
    • one year ago
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    yes right

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