## anonymous one year ago In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs.

1. anonymous

$L=\frac{ 1 }{ 2 }H \sqrt{2}$

2. anonymous

A) $11 \sqrt{3}\div 2$

3. anonymous

B) $11\sqrt{2}\div 2$

4. anonymous

C) $11 \sqrt{2}$

5. anonymous

You don't really need to put the choices out, just plug in the H of the formula i gave you and you'll be good...

6. anonymous

i dont have a calculator on me

7. anonymous

You don't need one...

8. anonymous

im not good with doing numbers in my head

9. anonymous

H=Hypotenuse. So put the H in for the formula and tell me what you get

10. anonymous

i know what H is

11. anonymous

wait so its C?

12. anonymous

No

13. anonymous

$L=H \sqrt{2} \div 2$

14. anonymous

$H=11$

15. anonymous

I hope you know that I'm just re-stating my first formula, re-arranged in a different way, right?