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anonymous

  • one year ago

Help me please i only want the answer ill fan u and give u a medal TY Admission to the Pie Eating Contest is $1.50 for children and $4 for adults. On a certain day, 2200 people came to watch and $5050 is collected. How many children and adults attended the Contest? Show ALL work. Let x = number of children Let y = number of adults A. Write 2 equations to model this system: B. Solve the first equation for x (get the x alone on 1 side): 5 points C. Use Substitution to solve the equations and determine how many adults and how many children attended

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  1. anonymous
    • one year ago
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    help

  2. anonymous
    • one year ago
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    Ok

  3. anonymous
    • one year ago
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    What are you working on I gotta know what type of problem to make

  4. anonymous
    • one year ago
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    i need to explain the work and find out Admission to the Pie Eating Contest is $1.50 for children and $4 for adults. On a certain day, 2200 people came to watch and $5050 is collected. How many children and adults attended the Contest? Show ALL work. Let x = number of children Let y = number of adults A. Write 2 equations to model this system: B. Solve the first equation for x (get the x alone on 1 side): 5 points C. Use Substitution to solve the equations and determine how many adults and how many children attended

  5. anonymous
    • one year ago
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    @Michele_Laino

  6. Michele_Laino
    • one year ago
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    your problem can be modeled by the subsequent system: \[\left\{ {\begin{array}{*{20}{c}} {1.5x + 4y = 5050} \\ {x + y = 2200} \end{array}} \right.\] the first equation comes from the total money collected, the second one comes from the total number of person who wants to assist to the performance

  7. anonymous
    • one year ago
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    so is that for part a ?

  8. Michele_Laino
    • one year ago
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    yes!

  9. Michele_Laino
    • one year ago
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    from the second equation I get: x= 2200-y, now I substitute into the first one so I get: 1.5(2200-y)+4*y=5050 please solve for y

  10. anonymous
    • one year ago
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    4(2200-x)+1.5*x=5050 ? is that correct ?

  11. Michele_Laino
    • one year ago
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    yes!

  12. Michele_Laino
    • one year ago
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    what is x?

  13. anonymous
    • one year ago
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    the amount of children

  14. anonymous
    • one year ago
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    now can u help with part C pls and TY

  15. Michele_Laino
    • one year ago
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    we have to simplify that equation, so we get: 8800-4x+1.5x=5050 please continue

  16. anonymous
    • one year ago
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    how did u get 8800 ?

  17. anonymous
    • one year ago
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    i dont get it

  18. Michele_Laino
    • one year ago
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    4*2200= 8800

  19. anonymous
    • one year ago
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    oh ok i get it TY

  20. anonymous
    • one year ago
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    so 3300-1.5x+4y=5500 am i right ?

  21. Michele_Laino
    • one year ago
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    after that simplification, you should get this equation: 2.5 x= 3750

  22. Michele_Laino
    • one year ago
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    more steps: 8800-2.5x=5050

  23. Michele_Laino
    • one year ago
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    2.5 x= 8800-5050

  24. Michele_Laino
    • one year ago
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    so: x=3750/2.5=...?

  25. Michele_Laino
    • one year ago
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    what is: \[\Large x = \frac{{3750}}{{2.5}} = ...?\]

  26. anonymous
    • one year ago
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    1500

  27. Michele_Laino
    • one year ago
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    ok!

  28. Michele_Laino
    • one year ago
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    now, we have: y=2200-x=2200-1500=...?

  29. anonymous
    • one year ago
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    700

  30. Michele_Laino
    • one year ago
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    that's right!

  31. anonymous
    • one year ago
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    ty soooooo much can you organize according to the answers to the Parts pls ill right a review and fan and medal you ty again

  32. Michele_Laino
    • one year ago
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    part A: the requested system is: \[\left\{ {\begin{array}{*{20}{c}} {1.5x + 4y = 5050} \\ {x + y = 2200} \end{array}} \right.\]

  33. Michele_Laino
    • one year ago
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    part B: the requested equation is: \[2.5x = 3750\]

  34. Michele_Laino
    • one year ago
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    part C: the requested solution is: \[\left\{ {\begin{array}{*{20}{c}} {x = 1500} \\ {y = 700} \end{array}} \right.\]

  35. anonymous
    • one year ago
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    yaaaaaaay TY sooooo sooooooo sooooooo much im happy i found you

  36. Michele_Laino
    • one year ago
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    thanks!!!!! :)

  37. anonymous
    • one year ago
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    np

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