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  • one year ago

The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.

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  1. anonymous
    • one year ago
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    Part A: The projectile was launched from a height of 90 feet with an initial velocity of 50 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 28 + 48.8t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

  2. anonymous
    • one year ago
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    I already have the answers to A & B A: -16t^2 + 50t + 90 = 0 Solve for t using the quadratic formula, then discard the negative solution: t = (25 + √2065) / 16 = 4.4 seconds B: Supposing you have calculus, take the derivative of the function in part A and set it equal to zero: -32t + 50 = 0 t = 50/32 = 25/16 sec is the time at which the maximum height will be reached, so evaluate the original function at t = 25/16: H = 129 ft

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