anonymous
  • anonymous
In an electric field of strength 0.50 N/C, a test charge experiences a force of 2.50 × 10^-4 N in the same direction as the field. What is the magnitude of the test charge? A. -5.00 × 10^-4 C B. -2.50 × 10^-4 C C. +2.50 × 10^-4 C D. +5.00 × 10^-4 C
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
the requested charge (magnitude) is given by the subsequent formula: \[\large Q = \frac{F}{E} = \frac{{2.5 \times {{10}^{ - 4}}}}{{0.5}}\]
anonymous
  • anonymous
ok! so we get 5E-4? so our answer is choice D? :O
Michele_Laino
  • Michele_Laino
that's right! Since vectors E and Q have the same orientation |dw:1433440851327:dw|

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anonymous
  • anonymous
ahh okie!! yay!! thank you!:)
Michele_Laino
  • Michele_Laino
vectors E and F
Michele_Laino
  • Michele_Laino
:)

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