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anonymous

  • one year ago

In an electric field of strength 0.50 N/C, a test charge experiences a force of 2.50 × 10^-4 N in the same direction as the field. What is the magnitude of the test charge? A. -5.00 × 10^-4 C B. -2.50 × 10^-4 C C. +2.50 × 10^-4 C D. +5.00 × 10^-4 C

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  1. Michele_Laino
    • one year ago
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    the requested charge (magnitude) is given by the subsequent formula: \[\large Q = \frac{F}{E} = \frac{{2.5 \times {{10}^{ - 4}}}}{{0.5}}\]

  2. anonymous
    • one year ago
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    ok! so we get 5E-4? so our answer is choice D? :O

  3. Michele_Laino
    • one year ago
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    that's right! Since vectors E and Q have the same orientation |dw:1433440851327:dw|

  4. anonymous
    • one year ago
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    ahh okie!! yay!! thank you!:)

  5. Michele_Laino
    • one year ago
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    vectors E and F

  6. Michele_Laino
    • one year ago
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    :)

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