anonymous one year ago In an electric field of strength 0.50 N/C, a test charge experiences a force of 2.50 × 10^-4 N in the same direction as the field. What is the magnitude of the test charge? A. -5.00 × 10^-4 C B. -2.50 × 10^-4 C C. +2.50 × 10^-4 C D. +5.00 × 10^-4 C

1. Michele_Laino

the requested charge (magnitude) is given by the subsequent formula: $\large Q = \frac{F}{E} = \frac{{2.5 \times {{10}^{ - 4}}}}{{0.5}}$

2. anonymous

ok! so we get 5E-4? so our answer is choice D? :O

3. Michele_Laino

that's right! Since vectors E and Q have the same orientation |dw:1433440851327:dw|

4. anonymous

ahh okie!! yay!! thank you!:)

5. Michele_Laino

vectors E and F

6. Michele_Laino

:)