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anonymous
 one year ago
Help me start this out please. I need to find the measure of x. Will medal as I always do :)
anonymous
 one year ago
Help me start this out please. I need to find the measure of x. Will medal as I always do :)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is a right triangle, such as this one. On side B is 12. On side C is 12. X is between the two.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0On side c is 13 My bad

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 May you be able to help me? :)

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1So it's this? dw:1433441809145:dw

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Okayyyy, if you know your triangles, you should know that 51213 is a special triangle like 345. So we can just replace a with 5. In order to find x, we could do either the sine, cosine, or tangent, your choice since we have all the sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im going to go with tan

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1Alright! So tangent is: \(\large \tan\theta=\frac{opposite}{adjacent} \) So for your triangle: dw:1433442229985:dw So \(\large \tan x=\frac{5}{12} \) Make sense?

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1In order to get the angle for x, just take the inverse tangent: \(\large x=\tan^{1}(5/12)\) Plug that into a calculator and you'll get the angle degree of x :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sorry i didnt respond fast enough but thank you for helping me!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.022.61 or rounded 22.62 Thank you <3 I got the answer :D

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.1It's alright, and yes, nice job :) You're welcome!
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